LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)
<h3>What is the limit of a function ?</h3>
The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.
It is given that
lim x->2 for f(x)
f(x) = 2x+1 x ≤2
f(x)= x² , x >2
When both the function tends to 2
Left Hand Limit
f(x) = 2 *2 +1
f(x) = 5
Right Hand Limit
f(x) = x² ,
f(x) = 4
LHL in not equal to RHL , Therefore the limit does not exists.
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Answer is in the attachment below.
Answer:
Center of the circle= (-9,6)
Radius = 5 units
Step-by-step explanation:
Once the equation of the circle has been written in the format
(x-h)²+(y-k)²=r² , (h,k) is the center while r is the radius of the circle.
From the given equation, -h=9 therefore h= -9.
-k = -6 therefore k = 6. r² = 25 therefore r= √25=5
Center of the circle= (-9,6) radius = 5 units
Solution -
We have 6 males and 6 females. And in each group we have to choose one male and a female
For the first group we have (6,6) options, after choosing one pair we have (5,5) options, then (4,4) options, then (3,3) options, then (2,2) options, then (1,1) options.
So the first has 36 possibilities, 6 possible males, 6 possible females. 6 times 6 is 36.
After picking up one male and female, we have 5 males and 5 females, 25 possibilities and so on.
Total we have 36×25×16×4×1 = 57600.
