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Hitman42 [59]
2 years ago
15

(5a^3-2)(5a^3+2) expand and combine like terms

Mathematics
1 answer:
joja [24]2 years ago
4 0

Step-by-step explanation:

(5a³-2)(5a³+2)

  1. 5a³×5a³+ 5a³×2 - 2× 5a³+ 5a³×2
  2. 5a³+10a³- 10a³ + 10a³
  3. 5a³+10a³ + 10a³-10a³
  4. 15a³ Answer
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Pls help I will not let me add the screenshot so I'm going to try and explain. so there is a rectangle the top measures 10m and
-BARSIC- [3]
Answer:

£23

Explanation:

6x10=60
2x1.5=3
3.14x2^2=12.566
60-3-12.566=44.433
44.43/10=4.43
5 bags
5x4.60=23
=£23
3 0
3 years ago
{x^2+6x-27/x^2-9x+18<br> how to solve step by step
Alika [10]

Answer:

Step-by-step explanation:

Step by Step Solution:

More Icon

STEP

1

:

5

Simplify ———————

x2 - 81

Trying to factor as a Difference of Squares:

1.1 Factoring: x2 - 81

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 81 is the square of 9

Check : x2 is the square of x1

Factorization is : (x + 9) • (x - 9)

Equation at the end of step

1

:

(((x2)-18x)+81) 5

———————————————•———————————

(((x2)-6x)-27) (x+9)•(x-9)

STEP

2

:

x2 - 18x + 81

Simplify —————————————

x2 - 6x - 27

Trying to factor by splitting the middle term

2.1 Factoring x2 - 18x + 81

The first term is, x2 its coefficient is 1 .

The middle term is, -18x its coefficient is -18 .

The last term, "the constant", is +81

Step-1 : Multiply the coefficient of the first term by the constant 1 • 81 = 81

Step-2 : Find two factors of 81 whose sum equals the coefficient of the middle term, which is -18 .

-81 + -1 = -82

-27 + -3 = -30

-9 + -9 = -18 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and -9

x2 - 9x - 9x - 81

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-9)

Add up the last 2 terms, pulling out common factors :

9 • (x-9)

Step-5 : Add up the four terms of step 4 :

(x-9) • (x-9)

Which is the desired factorization

Trying to factor by splitting the middle term

2.2 Factoring x2-6x-27

The first term is, x2 its coefficient is 1 .

The middle term is, -6x its coefficient is -6 .

The last term, "the constant", is -27

Step-1 : Multiply the coefficient of the first term by the constant 1 • -27 = -27

Step-2 : Find two factors of -27 whose sum equals the coefficient of the middle term, which is -6 .

-27 + 1 = -26

-9 + 3 = -6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 3

x2 - 9x + 3x - 27

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-9)

Add up the last 2 terms, pulling out common factors :

3 • (x-9)

Step-5 : Add up the four terms of step 4 :

(x+3) • (x-9)

Which is the desired factorization

Canceling Out :

2.3 Cancel out (x-9) which appears on both sides of the fraction line.

Equation at the end of step

2

:

(x - 9) 5

——————— • —————————————————

x + 3 (x + 9) • (x - 9)

STEP

3

:

Canceling Out

3.1 Cancel out (x-9) which appears on both sides of the fraction line.

Final result :

5

—————————————————

(x + 3) • (x + 9)

5 0
3 years ago
What is x in the equation in -4(3x+7)= 4
Nana76 [90]

Answer:

-12x-28=4

-12x=32

x=-16/3

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
What is a solution to the equation 5x + 2y = -1?
Hunter-Best [27]
The answer to the solution of the equation 5x+2y=-1 is 1,-3)
5 0
3 years ago
your grades on tests 1 2 and 4 are 82 76 and 90. unfortunately you cut the third test and received a 0. If you have one test lef
Dmitrij [34]

Answer:  No, he can't pass the course.

Explanation:

Since we have given that

Marks on tests 1, 2, and 4 are given by

82, 76, 90 respectively.

Unfortunately, he cut the third test and receive a 0.

According to question, we have given that passing grade for the course is 70, and his one test left to take ,

Let the marks obtained in fifth test be x

So,

\frac{82+76+90+0+x}{5}=70\\\\248+x=5\times 70=350\\\\x=350-248\\\\x=102

And it is not possible to get 102 over 100.

so, he can't still pass the course.

Hence, No, he can't pass the course.

8 0
3 years ago
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