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liraira [26]
4 years ago
5

Calculate the cost of Job 845 using a machine hour departmental overhead rate for the Milling Department ($32 per hour) and a di

rect hour overhead rate for the Finishing Department ($102 per hour). (Round your answer to the nearest dollar.)Assume that manufacturing overhead for Goldratt Company consisted of the following activities and costs:Setup (1,000 setup hours) $118,000Production scheduling (400 batches) 60,000Production engineering (60 change orders) 150,000Supervision (2,000 direct labor hours) 46,000Machine maintenance (12,000 machine hours) 60,000Total activity costs $434,000The following additional data were provided for Job 845:Direct materials costs $7,000Direct labor cost (5 Milling direct labor hours;35 Finishing direct labor hours) $1,000Setup hours 5 hoursProduction scheduling 1 batchMachine hours used (25 Milling machine hours;5 Finishing machine hours) 30 hoursProduction engineering 3 change orders

Business
2 answers:
Zanzabum4 years ago
7 0

Answer:

Total job cost= 12370$

Explanation:

Detailed solution is given in tabular form below:

kolbaska11 [484]4 years ago
5 0

Answer:

<em>Job 845:</em>

<u>departamental overhead</u> $ 4,370

Total cost  $ 12,370

<u>activity base overhead  </u>9310

Total cost: $ 17,310

Explanation:

Job 845

Materials 7000

Labort     1,000

Milling overherad:

25 machinie hours x $32 = $ 800

Finishing overhead

35 labor hours x $102 = $ 3,570

Total cost: $ 12,370

activity base overhead:

\left[\begin{array}{ccccc}Activity&Driver&cost&Total&Rate\\$Setup&setup&118000&1000&118\\$Scheduling&matches&60000&400&150\\$engineering&orders&150000&60&2500\\$supervision&DLH&46000&2000&23\\$maintenance&MH&60000&12000&5\\\end{array}\right]

Now we multiply by the rate:

\left[\begin{array}{ccccc}Activity&Rate&job 845&Allocate Rims\\$Setup&118&5&590\\$Scheduling&150&1&150\\$engineering&2500&3&7,500\\$supervision&23&40&920\\$maintenance&5&30&150\\$Total Overhead&&&9,310\\\end{array}\right]

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$16,281$⁢16,281 is invested, part at 15%15% and the rest at 13%13%. If the interest earned from the amount invested at 15%15% ex
aleksandr82 [10.1K]

Answer:

Ans. The amount invested at 13% was $1,595.97 and $14,685.03 were invested at 15%

Explanation:

Hi, you can solve this by using 2 equations, so let X be the portion of the money invested at 15% and Y be the amount invested at 13%. So the equation for the whole amount is:

X+Y=16,281

Now, the problem says that the money that you earn by investing at 15% exceeds the money received as interest in your investment of 13% by $1,995.27, this leads us to the second equation.

0.15X=0.13Y+1995.27

Now, to make it a little more friendly, we just have to go ahead and divide everything by 0.15, so we get.

X=0.8667Y+13,301.8

Now, in our first equation, we substitute X fo 0.8867(Y)+13,301.8 and we will see this.

0.8667Y+13,301.8+Y=16,281

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Y=\frac{2,979.2}{1.8667} =1,595.97

So the money invested at 13% was $1,595.97 therefore, the money invested at 15% was $16,281 - $1,595.97 = $14,685.03

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And the money invested at 13% will return

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Substracting, we would found that the difference is:

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