Area=1/2 times bas time height
base=10
height=12
area=1/2 times 10 times 12
area=5 times 12
area=60 in^2
3rd one
Answer:
Step-by-step explanation:
To find the slope of the line, you have to use a slope formula.
<u>Slope formula:</u>
⇒ y2=(-15)
⇒ y1=1
⇒ x2=1
⇒ x1=(-1)
<u>Rewrite the whole problem down.</u>
- <u>So, the slope is -8, which is our answer.</u>
I hope this helps you! Let me know if my answer is wrong or not.
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
y=1.25x+470
y=2.00x+350
Step-by-step explanation:
The linear equation form is y=mx+b so for m you but the amount that depends on x and b is the constant.