Answer:
Step-by-step explanation:
A
The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
I think this system is consistent and dependent
Answer:
<u>Two</u>
============================
Step-by-step explanation:
The solution for any system of equations is the intersection points between the graph that representing the system of equation.
So, for the given system of equation, we have a circle and a parabola.
As shown in the figure, The circle and parabola are intersects at two points
So, there are two solutions for the system of equations on the graph.
So, The answer is option two.
X-3y, x=3, y=-2
(3)-3(-2)
(3)+(3*2)
3+6=9
