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Sveta_85 [38]
3 years ago
13

Hannah and Anthony are siblings who have ages that are consecutive odd integers . The sum of their ages is 92 . Which equations

can be used to d=find Hannah's age, h,if she is the older sibling?
Mathematics
1 answer:
Sliva [168]3 years ago
4 0

Is there any options to pick out of?

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Please help with this problem!
Sergeeva-Olga [200]

Answer:

hnukunykgbuykgkuyu

Step-by-step explanation:

6 0
3 years ago
A random variableX= {0, 1, 2, 3, ...} has cumulative distribution function.a) Calculate the probability that 3 ≤X≤ 5.b) Find the
olchik [2.2K]

Answer:

a) P ( 3 ≤X≤ 5 ) = 0.02619

b) E(X) = 1

Step-by-step explanation:

Given:

- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:

                    F(X) = P ( X =< x) = 1 - \frac{1}{(x+1)*(x+2)}

Find:

a.Calculate the probability that 3 ≤X≤ 5

b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that

Solution:

- The CDF gives the probability of (X < x) for any value of x. So to compute the P (  3 ≤X≤ 5 ) we will set the limits.

                   F(X) = P ( 3=

- The Expected Value can be determined by sum to infinity of CDF:

                   E(X) = Σ ( 1 - F(X) )

                   E(X) = \frac{1}{(x+1)*(x+2)} = \frac{1}{(x+1)} - \frac{1}{(x+2)} \\\\= \frac{1}{(1)} - \frac{1}{(2)}\\\\= \frac{1}{(2)} - \frac{1}{(3)} \\\\=  \frac{1}{(3)} - \frac{1}{(4)}\\\\= ............................................\\\\=  \frac{1}{(n)} - \frac{1}{(n+1)}\\\\=  \frac{1}{(n+1)} - \frac{1}{(n+ 2)}

                   E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]  

                   E(X) = 1

8 0
3 years ago
Expand 3(z+3) please help me solve this
mojhsa [17]

Answer:

3(z+3) = 3z + 9 if thats what your asking

Step-by-step explanation:

7 0
3 years ago
Lisa and Beverly had just $5 to spend for an afterschool snack. They could’ve bought 2 hamburgers and 1 carton of milk with no c
Elanso [62]
1 dollar and 40 cents.
4 0
3 years ago
Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of
fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given :  the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Since, given the difference of the squares of the numbers is 5 that is (x^2-y^2)^2=5

And the product of the numbers is 6 that is xy=6

Using identity, we have,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Substitute, we have,

(x^2+y^2)^2=(5)^2+(2(6))^2

Simplify, we have,

(x^2+y^2)^2=25+144

(x^2+y^2)^2=169

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0
3 years ago
Read 2 more answers
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