Here is a simple way we can do this.
We have six blanks.
__ __ __ __ __ __
Now, we have 13 possible options to fill in blank number one.
13 __ __ __ __ __
Now we have 12 possible options to fill in blank number two because one person has already been chosen.
13 12 __ __ __ __
Now we have 11 possible options for blank number three.
13 12 11 __ __ __
Now we have 10 possible options for blank number four.
13 12 11 10 __ __
And so forth until we get:
13 12 11 10 9 8
Now we just have to multiply the numbers all together.
13 * 12 * 11 * 10 * 9 * 8
is equal to:
1235520 ways.
Problem 2
Plot point L anywhere that isn't on segment JK. Draw a line through point L. I find it helps to make the lines parallel.
Next, use a compass to measure the width of segment JK. Keeping this same width, transfer the nonpencil end of the compass to point L. Draw an arc that crosses the line through L.
Mark this intersection point M. Lastly, use a pen or marker to form segment LM and erase everything else of that line.
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Problem 3
The ideas of the previous problem will be used here. We copied segment JK to form congruent segment LM. So JK = LM.
The same steps will be used to form segment GN where GN = EF. In other words, segment GN is a perfect copy of segment EF.
If you repeat these steps again, you'll get another segment of the same length. This segment goes from point N to point H. So NH = GN = EF
Then we can say,
GH = GN + NH
GH = EF + EF
GH = 2*EF
Equation B is written in vertex form, which means you can read the vertex (extreme value) from the numbers in the equation.
Vertex form is
y = a(x -h)² + k
where the vertex (extreme point) is (h, k). Whether that is a maximum or a minimum depends on the sign of "a". When "a" is negative, the graph is a parabola that opens downward, so the vertex is a maximum.
Equation
B reveals its extreme value without needing to be altered.
The extreme value of this equation is a
maximum at the point
(2, 5).
Answer:
The dog's running area is approximately 942 feet².
Step-by-step explanation:
The dog is leashed to a fixed point, the leash has a length of 20 ft, therefore he can rotate around that point at the maximum distance equal to the length of the leash. This pattern forms a circle, but there is an obstruction, which is the corner of the house. This obstruction takes an arc of the original circle, so the running area of the dog is the area of the whole circle minus the area of the arc formed by the corner of the house.

The dog's running area is approximately 942 feet².