The solution is attached. I hope it helps
Answer:
df
Step-by-step explanation:
Remember how the tangent function is defined as

Now where exactly are the vertical assymptotes? Well, where cosx = 0, because anything over 0 is undefined, and where a value is undefined, you are required to draw a vertical assymptote.
Now where exactly are the x interecepts? Well, where sinx = 0, because remember, an x-intercept is where y = 0, or where it crosses the x-axis, meaning where the tangent function is equal to 0.
So the x-intercepts are at where sinx = 0.
Answer:
23, 25, 27
Step-by-step explanation:
n + (n+2) + (n+4) = 4n - 17
3n + 6 = 4n - 17
3n - 4n = -17 - 6
-n = -23
n = 23
therefore,
23, 25, 27 are the 3 consecutive odd integers
First find the critical points of <em>f</em> :



so the point (1, 0) is the only critical point, at which we have

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

Find the critical points of <em>g</em> :



where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at




So <em>f</em> has a minimum of -7 and a maximum of 299.