All categories

4 years ago

❄️Please help❄

Mathematics

1 answer:

kondor19780726 [428]4 years ago

7 0

Answer:

When a system of equations have one solution, it is a consistent independent system.

In a consistent independent system, the lines cross each other at one point, called the point of intersection.

Here is an example of a consistent independent system:

You might be interested in

Debora drove 400 miles on her vacation. She drove an average of 1.5 times faster in the second 200 miles of her trip than she di

vodomira [7]

$t=\dfrac{s}{v}$
Time, she spent driving the first 200 miles:
$\dfrac{200}{x}$
Time, she spent driving the second 200 miles:
$\dfrac{200}{1.5\cdot x}$

Total time:
$\dfrac{200}{x}+\dfrac{200}{1.5\cdot x}=\dfrac{200}{x}\cdot \dfrac{1.5}{1.5}+\dfrac{200}{1.5\cdot x}=\dfrac{300}{1.5\cdot x}+\dfrac{200}{1.5\cdot x}=\dfrac{500}{1.5\cdot x}=\boxed{\dfrac{1000}{3\cdot x}}$

6 0

3 years ago

I need help.please help me

Mariana [72]

Answer:

1) r >-5 2) x >9

Step-by-step explanation:

4 0

3 years ago

Complete the equation 0+_=91

ira [324]

The equation is 0+91=91. This is because 91+0=91. So, x=91.

5 0

3 years ago

Read 2 more answers

Need help with this question asap!!

Juli2301 [7.4K]

So I took the test and my teacher said to label all of the degrees so

angle 1,3,5,7,9,11,13,15 all = 95 degrees

angle 2,4,6,8,10,12,14,16 all = 85 degrees

I know 1 and 3 are vertical angles

3 and 8 are same side interior angle

4 and 14 alternate interior angles

6 and 12 are alternate exterior angles

13 and 9 are corresponding angles

4 and 7 are same side interior angles

I believe these are correct but you might want to double check with some other source

3 0

3 years ago

The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

The point $(1\frac{1}{2},1)$ won't be on the graph because the corresponding value of y for $x = 1\frac{1}{2}$ is $y = 2\frac{1}{4}$

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

The point $(4,6)$ would be on the graph because the corresponding value of y for $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

The point $(18,12)$ wouldn't be on the graph because the corresponding value of y for $x = 18$ is $y = 12$

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

The point $(0,0)$ would be on the graph because the corresponding value of y for $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

The point $(2\frac{1}{2},3\frac{3}{4})$ would be on the graph because the corresponding value of y for $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

3 0

3 years ago