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Tom [10]
4 years ago
15

PLZZZZZZZZZ HELP!!!!!!!!!!!!! Ty!!!!!!!!!! ANYONE PLZ HELP!

Mathematics
1 answer:
marishachu [46]4 years ago
7 0

Answer: its the first answer choice

ANSWER:x^3 -9x^2+25x

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Graphing Quadratic Functions (help please )
Reil [10]

Answer:

#1

Zeroes: x = 4, x = -6

The vertex is at ( -1 , 50 )

Step-by-step explanation:

I'll do the first one, you try the rest

All of these are written in y = a(x - x1)(x - x2) where x1 and x2 are given and x are the two different zeroes (or x-intercepts)

f(x) = -2(x-4)(x+6)

The zeroes are x - 4 = 0 and x + 6 = 0 if you solve, you get 4 and -6

Zeroes: x = 4, x = -6

The x value of the vertex can be found using -b/2a (in the form ax^2 + bx + c)

First expand f(x)

-2(x^2 + 2x - 24) => -2x^2 - 4x + 48

b = -4 and a = -2

-(-4)/2(-2) = 4/-4 = -1

the x-value of the vertex is -1

Now substitute -1 as x to find the y-value of the vertex

-2(-1-4)(-1+6) = -2(-5)(5) = 50 <= y-value of vertex

The vertex is at ( -1 , 50 )

6 0
3 years ago
A cashier collects 124 bills totaling $920 dollars. Assuming that the cashier collects $5, $10, and $20 bills, and that she coll
musickatia [10]
Let the no. of $10 bills be x, the no. of $5 bills be 2x, and the no. of $20 bills be y.

<span>A cashier collects 124 bills => x + 2x + y = 124  => 3x +y =124

</span>totaling $920 dollars => ($10)(x) + ($5)(2x) + ($20)(y) = $920 => 20x + 20y = 920

Now you got 2 equations :
3x +y =124 &
20x + 20y = 920

3x +y =124 => y=124-3x
Then Sub y=124-3x into 20x + 20y = 920,
ie. 20x + 20(124-3x) = 920 
     20x + 2480 - 60x = 920
     2480 - 40x = 920
      2480 - 920 = 40x
               1560 = 40x
                      x = 39

6 0
4 years ago
Let t = cosA + sinA<br> find values of t if <br> 2 - sin2A = 2(cosA + sinA)
Zinaida [17]

2 - \sin(2A) = 2(\cos A + \sin A)\\\\2-2\sin A\cos A=2\cos A+2\sin A\\\\2\sin A\cos A+2\cos A+2\sin A-2=0\\\\1+2\sin A\cos A+2\cos A+2\sin A-3=0\\\\\sin^2 A+\cos^2 A+2\sin A\cos A+2\cos A+2\sin A-3=0\\\\(\sin A+\cos A)^2+2\cos A+2\sin A-3=0\\\\(\sin A+\cos A)^2+2(\cos A+\sin A)-3=0\\\\\\t^2+2t-3=0\\\\t^2+2t+1-4=0\\\\(t+1)^2=4\\\\t+1=2\qquad\vee \qquad t+1=-2\\\\\\\boxed{t=1\qquad\vee\qquad t=-3}

When A\in\mathbb{R}

t=\cos A+\sin A\in[-\sqrt{2};\sqrt{2}]\approx[-1.4142;1.4142]

and there is only one answer t = 1.

For A\in\mathbb{C} both values are correct.

4 0
4 years ago
Anyone know this? please help and Thank you very much!!!
Monica [59]

(9+7i)(6+3i)\\\\=54+27i + 42i + 21i^2\\\\=54+69i -21~~~;[i^2 =-1]\\\\=33+69i

7 0
2 years ago
A candy bar box is in the shape of a triangular prism. The volume of the box is 1,200 cubic centimeters. Part A: What is the hei
Rus_ich [418]
Hello!

A) 10 cm

As we can see in the diagram, the height of the prism is 10 cm.

B) 850 cm

To find the answer we need to find the surface area of the candy box. To do so you add up the area of each face, as seen below.

65(triangle)+65 (triangle)+200 (base)+260(side)+260(side).=850.

I hope this helps!
5 0
4 years ago
Read 2 more answers
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