Answer:
#1
Zeroes: x = 4, x = -6
The vertex is at ( -1 , 50 )
Step-by-step explanation:
I'll do the first one, you try the rest
All of these are written in y = a(x - x1)(x - x2) where x1 and x2 are given and x are the two different zeroes (or x-intercepts)
f(x) = -2(x-4)(x+6)
The zeroes are x - 4 = 0 and x + 6 = 0 if you solve, you get 4 and -6
Zeroes: x = 4, x = -6
The x value of the vertex can be found using -b/2a (in the form ax^2 + bx + c)
First expand f(x)
-2(x^2 + 2x - 24) => -2x^2 - 4x + 48
b = -4 and a = -2
-(-4)/2(-2) = 4/-4 = -1
the x-value of the vertex is -1
Now substitute -1 as x to find the y-value of the vertex
-2(-1-4)(-1+6) = -2(-5)(5) = 50 <= y-value of vertex
The vertex is at ( -1 , 50 )
Let the no. of $10 bills be x, the no. of $5 bills be 2x, and the no. of $20 bills be y.
<span>A cashier collects 124 bills => x + 2x + y = 124 => 3x +y =124
</span>totaling $920 dollars => ($10)(x) + ($5)(2x) + ($20)(y) = $920 => 20x + 20y = 920
Now you got 2 equations :
3x +y =124 &
20x + 20y = 920
3x +y =124 => y=124-3x
Then Sub y=124-3x into 20x + 20y = 920,
ie. 20x + 20(124-3x) = 920
20x + 2480 - 60x = 920
2480 - 40x = 920
2480 - 920 = 40x
1560 = 40x
x = 39
When 
![t=\cos A+\sin A\in[-\sqrt{2};\sqrt{2}]\approx[-1.4142;1.4142]](https://tex.z-dn.net/?f=%20t%3D%5Ccos%20A%2B%5Csin%20A%5Cin%5B-%5Csqrt%7B2%7D%3B%5Csqrt%7B2%7D%5D%5Capprox%5B-1.4142%3B1.4142%5D%20)
and there is only one answer t = 1.
For 
both values are correct.
Hello!
A) 10 cm
As we can see in the diagram, the height of the prism is 10 cm.
B) 850 cm
To find the answer we need to find the surface area of the candy box. To do so you add up the area of each face, as seen below.
65(triangle)+65 (triangle)+200 (base)+260(side)+260(side).=850.
I hope this helps!
