Question

Which parameter of a projectile depends on the horizontal as well as the vertical component of velocity of projection?

Answer 1

Its the angle of launch, its one of many variables that will effect the over all out come of this test, angle at the ground and launch and well you get the point.

Answer 2

Answer:

range and angle of launch

Explanation:

Let the horizontal component of velocity be VCosθ = Vx and the vertical component of velocity is VSinθ = Vy.

Here , θ be the angle of projection.

So, if we divide the VSinθ by VCosθ, we get the value of Tanθ, i.e., we get the value of angle of launch.

Now we know that the formula fr the range is given by

$R = \frac{V^{2}\times Sin2\Theta }{g}$

We can write it as

$R = \frac{V^{2}\times 2\times Sin\Theta \times Cos\Theta }{g}$

Again we rewrite as

$R = \frac{2\times Vx\times Vy}{g}$

It shows that the range also depends on the horizontal and vertical component of velocity.