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sweet-ann [11.9K]
3 years ago
6

Prove that the rate of heat production in each of the two resistors connected in parallel is inversely proportional to the resis

tances
Physics
1 answer:
Viktor [21]3 years ago
4 0
I believe that the answer to the question provided above is that with increase in resistance provided with constant current, Power dissipated will be lessen since power loss is high. Low power dissipation has low heat production.
Hope my answer would be a great help for you.  
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Question 1 of 10
Novay_Z [31]

Answer:

C. 5.6 × 10^11 N/C

Explanation:

The electric field E at a distance R from a charge Q is given by

E = k\dfrac{Q}{R^2}

where k = 9*10^9Nm/C is the coulomb's constant.

Now, in our case

R = 0.0075m

Q = 0.0035C;

therefore,

E = (9*10^9)\dfrac{0.0035C}{(0.0075m)^2}

\boxed{E = 5.6*10^{11}N/C.}

which is choice C from the options given<em> (at least it resembles it).</em>

6 0
3 years ago
Trong thí nghiệm Y-âng về giao thoa ánh sáng : khoảng cách giữa hai khe là 0,5 mm ; khoảng cách từ mặt phẳng chứa hai khe đến mà
Natalija [7]

không có câu hỏi, trả lời như nào nhỉ?

8 0
3 years ago
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How would you obtain a mean value for the specific heat<br> capacity of a material?
lidiya [134]
The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.
8 0
3 years ago
A fuse in an electric circuit is a wire that is designed to melt, and thereby open the circuit, if the current exceeds a predete
zmey [24]

Answer:

The diameter of wire should be 4.04 \times 10^{-4} m

Explanation:

Given:

Current density J = 500 \times 10^{4} \frac{A}{m^{2} }

Current I = 0.64 A

From the formula of current density,

  J = \frac{I}{A}

Where A = area of cylindrical wire = \pi r^{2}

  \pi r^{2} = \frac{I}{J}

  r^{2} = \frac{I}{\pi J }

   r = \sqrt{\frac{0.64}{3.14 \times 500 \times 10^{4} } }

   r = 2.02 \times 10^{-4}m

For finding the diameter of wire,

   d = 2r

   d = 4.04 \times 10^{-4}m

Therefore, the diameter of wire should be 4.04 \times 10^{-4} m

8 0
3 years ago
What type of energy can take up space
Arada [10]

Answer:

Yes energy does take up space.

Explanation:

Every form of energy has a defining characteristic; sound is the vibration of molecules, electricity is the movement of electrons, and mass is the thing that take up space.

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