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3 years ago

What is reflection of light and its laws ?

Physics

2 answers:

Anit [1.1K]3 years ago

5 0

Answer:

So, put simply, reflection is light bouncing off surfaces. The law of reflection determines how the light bounces off a surface. The law of reflection states that the angle of incidence is equal to the angle of reflection.

<h2><em><u>Hope this helps..</u></em></h2>

ratelena [41]3 years ago

3 0

The law of reflection states that, on reflection from a smooth surface, the angle of the reflected ray is equal to the angle of the incident ray. (By convention, all angles in geometrical optics are measured with respect to the normal to the surface that is, to a line perpendicular to the surface.

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15 points. give me the method.

AveGali [126]

Answer:

$\boxed{{160 \: m(s)}^{ - 1} }$

Explanation:

$if \:the \: frequencies \: are \to \\ f_{1} = 640Hz \\ and \\f_{2} = 480Hz \: \\ but \: \boxed{v = f \gamma }: f = \frac{v}{ \gamma } \\ if \: \gamma_{1} - \gamma _{2} = 1 = \gamma \\ f_{1} - f_{2} = 640 - 480 = \boxed{ 160Hz} = f \\ v = f \gamma = 160 \times 1 = \boxed{{160 \: m(s)}^{ - 1} }$

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3 years ago

Force f⃗ =−10j^n is exerted on a particle at r⃗ =(7i^+5j^)m. part a what is the torque on the particle about the origin?

cluponka [151]

Answer:

Torque, $\tau=0i+0j-70k$

Explanation:

It is given that,

Force acting on the particle, $F=-10j\ N$

Position of the particle, $r=(7i+5j)\ m$

We need to find the torque on the particle about the origin. It is equal to the cross product of position and the force. Its formula is given by :

$\tau=r\times F$

$\tau=(7i+5j)\times (-10j)$

The cross product of vectors is given by :

$\tau=\begin{pmatrix}0&0&-70\end{pmatrix}$

$\tau=0i+0j-70k$

So, the torque on the particle about the origin $0i+0j-70k$ . Hence, this is the required solution.

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3 years ago

What is the final temperature of 0.5 kg of water initially at 18 °C after 65 kJ of

goldenfox [79]

A is the answe for the final temperatures

8 0

3 years ago

Read 2 more answers

What are the three longest wavelengths for standing waves on a 240-cm-long string that is fixed at both ends?

Irina18 [472]

For a standing wave if both ends are fixed, the wavelength must be such that the length of the string be an exact multiple of a half wavelength.
The longest wavelength must be such that the length of the string must be equal to half a wavelength, and therefore the wavelength must be double the length of the string; That is 240× 2 = 480 cm
The second longest wavelength must be such that the length of the string must be equal to a whole wavelength, so the second longest wavelength must be 240 cm.
The third longest wavelength must be such that the length of the string must be equal to 1.5 times the wavelength, so the wavelength must be 240/1.5 = 160 cm.

5 0

3 years ago

A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 44 ft/s2. What is the dist

elena55 [62]

Answer:

Distance, d = 61.13 ft

Explanation:

It is given that,

Initial speed of the car, u = 50 mi/h = 73.34 ft/s

Finally, it stops i.e. v = 0

Deceleration of the car, $a=-44\ ft/s^2$