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3 years ago

7

Jack rabbits are able to reach about 4mph. how fast is this in feet per second? 5,280= 1 mile

1 answer:

gavmur [86]3 years ago

5 0

The speed in feet per second may be calculated by the proper dimensional analysis and the given conversion factors. That is,
(40 mile / hr) x (5280 feet / 1 mile) x (1 hr / 3600 s) = 58.67 ft / s
Thus, the Jackrabbits' speed may also be expressed as 58.67 ft / s.

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A bag holds 11 beads 7 of the beads are red the rest are white two beads are taken at random work out the probability that one o

Anvisha [2.4K]

Answer:

28/55

Step-by-step explanation:

total no of beads are 11

red beads are 7

and white beads are 4

no of ways to take 2 beads from 11 beads are 11c2

that is( 11*10)/2=55

no of ways to take 1 red bead from 7 is 7c1 that is 7

no of ways to take 1 white bead from 4 is 4c1 is that is 4

required probability is( 7*4)/55=28/55

this question has already been answered on someone else's account so know this answer is 100% correct

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2 years ago

Describe an algorithm for finding the smallest integer in a finite sequence of natural numbers.

Crazy boy [7]

Answer:

min = a_1

for i:= 2 to n:

if $a_i$ < min then min = $a_i$

return min

Step-by-step explanation:

We call the algorithm "minimum" and a list of natural numbers $a_1, a_2, \cdot\cdot\cdot, a_n.$

So lets first set the minimum to $a_1$

min = a_1

now we want to check all the other numbers.

We can use a simple for loop, to find the minimum

min = a_1

for i:= 2 to n:

if $a_i$ < min then min = $a_i$

return min

5 0

1 year ago

Read 2 more answers

49-c< or equal to 45<br><br><br><br><br>thanks

m_a_m_a [10]

$49-c\leq45\qquad\text{subtract 49 from both sides}\\\\-c\leq-4\qquad\text{change the signs}\\\\\boxed{c\geq4}$

3 0

2 years ago

The equation x^2 + y^2 + 21 = 40 + 18y. What is the radius of this cookie?

trapecia [35]

Answer:

The radius is 10

Step-by-step explanation:

Given

$x^2 + y^2 + 21 = 40 + 18y.$

Required

The radius

Rewrite as:

$x^2 + y^2 - 18y = 40-21$

Subtract 81 from both sides

$x^2 + y^2 - 18y +81= 40-21+81$

Expand

$x^2 + y^2 - 9y - 9y +81= 40-21+81$

Factorize

$x^2 + y( y- 9) - 9(y -9)= 40-21+81$

Factor out y - 9

$x^2 + (y- 9) (y -9)= 40-21+81$

Express as squares

$x^2 + (y- 9)^2= 100$

$x^2 + (y- 9)= 10^2$

The equation of a circle is:

$(x - a)^2 + (y- b)= r^2$

By comparison:

$r^2=10^2$

$r = 10$

6 0

3 years ago

Check whether -2 and 2 are zeroes of the polynomial x+2

SVETLANKA909090 [29]

Answer:

-2 is a zero of the polynomial. 2 is not a zero of the polynomial.

Step-by-step explanation:

A value of x is a zero of a polynomial if when it is substituted for x in the polynomial, it makes the polynomial evaluate to zero.

The polynomial is x + 2

Let x = -2:

x + 2 = -2 + 2 = 0

-2 is a zero of the polynomial.

Let x = 2:

x + 2 = 2 + 2 = 4

2 is not a zero of the polynomial.

8 0

3 years ago