Answer:
y = (3/4)x + 2
Step-by-step explanation:
Slope-intercept form is y=mx+b where (x, y) is a point on the linear graph, m is the slope (rise/run), and b is the y-intercept (the y-value at which the graph passes through the y-axis).
Looking at the graph, we can see that the point at which the line crosses the y-axis is (0, 2) which makes it the y-intercept. Thus, the b in the slope-intercept form is 2.
Next, we are looking for the slope of the line. To do this, we can calculate the rise/run of the line by choosing to points on it. Since we already have the point (0, 2), we just need one more.
For example, the point (-4, -1) can be used. The slope can be found by ((y-y)/(x-x)) in which the first y and x values correspond with the first point and that of the second correspond with the second set. So in this case, m = (2-(-1))/(0-(-4)) = 3/4
Plugging in the calculated m and b value in the slope intercept equation, we get y = (3/4)x + 2
The answer is (4,8). I hope this helps.
The estimated number of ramps that can be cut from the board in discuss is; 6 ramps which is a reasonable assumption provided that each ramp is about 2 feet long.
b). The number of ramps that can be cut from the 12 1/2 feet long board is 6 and hence, the length of wood left is; 1/2.
<h3>What is the number of ramps that can be cut from the 12 1/2 feet long board?</h3>
It follows from the task content that skateboard ramps are made from a 12 1/2 feet long ramp.
Consequently, on the assumption that the quantity by measure of length of the board required to make one skateboard ramp is 2 feet, it follows that the estimated number of ramps that can be made from the board is; 12/2 = 6 skateboard ramps.
Ultimately, the amount of wood which is left over upon making the ramps is; 12 1/2 - 12 = 1/2.
Read more on division;
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In your problem about the finding the potential voltage at the center of the sphere where as its radius is 5cm is charge such that the potential of its surface is 10volts. So the possible answer to this is also 10 volts, because the potential in the center and in the surface of the sphere is constant and the same.