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NemiM [27]
2 years ago
13

A number that when multiplied equals 576 but when added equals 48

Mathematics
2 answers:
Flauer [41]2 years ago
5 0
...... 24 is the answer
jarptica [38.1K]2 years ago
5 0

Answer: 24 is the answer

<em>MARK ME BRAINLIST</em>

<em></em>

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Write the complex number in the form a + bi.
bonufazy [111]

Answer:

\frac{3}{2} + \frac{3\sqrt{3} }{2} i

Step-by-step explanation:

Using the exact value

cos60° = \frac{1}{2} and sin60° = \frac{\sqrt{3} }{2}, then

3(cos60° + isin60°)

= 3( \frac{1}{2} + \frac{\sqrt{3} }{2} i) ← distribute by 3

= \frac{3}{2} + \frac{3\sqrt{3} }{2} i ← in the form a + bi

7 0
3 years ago
Evaluate 1/3 m- 1- 1/2 n when m=21 and n=12
liq [111]

Answer:

0

Step-by-step explanation:

First we have to identify 1/3 m. We know that m is 21 and 1/3 of 21 is 7.

Then we find 1/2 on n which we know is 12 so 1/2 of 12 is 6.

Then we subtract. 7-1 is 6 and 6-6 is 0

Hope this helped!!! :D

4 0
3 years ago
Evaluate 3 to the power of 3+1⋅9+12<br><br> A.24<br> B.30<br> C.48<br> D.264
Crank
24..... hope I helped
5 0
2 years ago
Read 2 more answers
For accounting purposes, the value of assets (land, buildings, equipment) in a business are depreciated at a set rate per year.
lidiya [134]

Answer: $ 125987.80

Step-by-step explanation:

Given: The value, V(t) of $393,000 worth of assets after t years, that depreciate at 15% per year, is given by the formula

V (t)=V_o(b)^t, here V_o is the initial asset value  and b is the multiplicative decay factor.

The exponential decay function is given by ;-

f(x)=A(b)^x, where A is the initial value , x is the  times period and b is the multiplicative decay factor.

where b = 1-r, r is the rate of decay.

Since r = 15%=0.15

Therefore, b = 1-0.15=0.85

Now ,for 7 years , the value of assets is given by :-

V=393000(0.85)^7=125986.795\approx125987.80

Hence, the assets valued at after 7 years = $ 125987.80

4 0
2 years ago
Read 2 more answers
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
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