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Aleksandr-060686 [28]
3 years ago
6

WILL GIVE BRAINLIEST, please explain your answer! Calculate the area of the block "V" shown below. *Drawing not to scale

Mathematics
1 answer:
Vadim26 [7]3 years ago
8 0

Answer:

  132 mm^2

Step-by-step explanation:

The line added to the figure in the attachment shows it can be divided into two figures whose area is easily calculated.

  1. A parallelogram of base length 20 mm and height 4 mm:

     A = bh = (20 mm)(4 mm) = 80 mm^2

  2. A trapezoid with bases 32 mm and 20 mm, and height 2 mm:

     A = (1/2)(b1 +b2)h = (1/2)(32 mm +20 mm)(2 mm) = 52 mm^2

The total area of the figure is then ...

  80 mm^2 +52 mm^2 = 132 mm^2

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Answer:

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Step-by-step explanation:

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Cross-multiplying

C = 6DE = 6 x 52 = 312 CM

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Step-by-step explanation:

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Find the 13th term of the arithmetic sequence -3x – 1,42 + 4,112 + 9, ...
Strike441 [17]

Answer:

The 13th term is 81<em>x</em> + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

\displaystle -3x -1, \, 4x +4, \, 11x  + 9 \dots

And we want to find the 13th term.

Recall that for an arithmetic sequence, each subsequent term only differ by a common difference <em>d</em>. In other words:

\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}

Find the common difference by subtracting the first term from the second:

d = (4x+4) - (-3x - 1)

Distribute:

d = (4x + 4) + (3x + 1)

Combine like terms. Hence:

d = 7x + 5

The common difference is (7<em>x</em> + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

\displaystyle x_n = a + d(n-1)

Where <em>a</em> is the initial term and <em>d</em> is the common difference.

The initial term is (-3<em>x</em> - 1) and the common difference is (7<em>x</em> + 5). Hence:

\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)

To find the 13th term, let <em>n</em> = 13. Hence:

\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)

Simplify:

\displaystyle \begin{aligned}x_{13} &= (-3x-1) + (7x+5)(12) \\ &= (-3x - 1) +(84x + 60) \\ &= 81x + 59 \end{aligned}

The 13th term is 81<em>x</em> + 59.

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