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Aleksandr-060686 [28]
3 years ago
6

WILL GIVE BRAINLIEST, please explain your answer! Calculate the area of the block "V" shown below. *Drawing not to scale

Mathematics
1 answer:
Vadim26 [7]3 years ago
8 0

Answer:

  132 mm^2

Step-by-step explanation:

The line added to the figure in the attachment shows it can be divided into two figures whose area is easily calculated.

  1. A parallelogram of base length 20 mm and height 4 mm:

     A = bh = (20 mm)(4 mm) = 80 mm^2

  2. A trapezoid with bases 32 mm and 20 mm, and height 2 mm:

     A = (1/2)(b1 +b2)h = (1/2)(32 mm +20 mm)(2 mm) = 52 mm^2

The total area of the figure is then ...

  80 mm^2 +52 mm^2 = 132 mm^2

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Remember ... the "solution" is the number that 'g' must be
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The original equation:   You said that  -2 = g - 9

Now, let's add  9  to each side:             7 = g .

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3 years ago
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Write 1.48 repeating as a mixed number as a mixed number
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2 years ago
In a basketball game Anya makes 14 baskets. Some of these baskets were worth 2-points and others were worth 3-points. In total s
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Answer:

She made 12 two point basket.

Step-by-step explanation:

Assuming the number of 2 point basket is x and that of 3 point basket is y.

Based on the question the total numbers of basket is 14, that is x + y = 14 , and the total numbers of points is 30, which helps us with our second equation 2(x) +3(y)=30.

x + y = 14 eqn 1

2(x) +3(y)=30 eqn 2

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7 0
3 years ago
Michelle and Natasha each had to repair their new iPhones. The initial cost of each repair is $ 100. Michelle and Natasha each h
worty [1.4K]

Answer:Michelle

And 50

Step-by-step explanation:

6 0
2 years ago
Andrew is about to leave for school. If he walks at a speed of 50 meters per minute, he will arrive 3 minutes after the bell rin
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Answer:

The answer is: 13 minutes

Step-by-step explanation:

First Let us form equations with the statements in the two scenario

time=\frac{distance}{speed}

Let the time in which the bell rings be 'x'

1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes

3 + x =\frac{distance}{50}\\distance = 50(3+x) - - - - - (1)

2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

x - 3 = \frac{distance}{80} \\distance = 80(x-3)   - - - - - (2)

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

50(3+x)=80(x-3)

150 +50x=80x-240\\

Next, collecting like terms:

150 + 240 = 80x - 50x\\390 = 30x\\30x = 390\\

dividing both sides by 3:

x =  390÷30 = 13

∴ x = 13 minutes

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