WILL GIVE BRAINLIEST, please explain your answer! Calculate the area of the block "V" shown below. *Drawing not to scale
1 answer:
Answer:
132 mm^2
Step-by-step explanation:
The line added to the figure in the attachment shows it can be divided into two figures whose area is easily calculated.
1. A parallelogram of base length 20 mm and height 4 mm:
A = bh = (20 mm)(4 mm) = 80 mm^2
2. A trapezoid with bases 32 mm and 20 mm, and height 2 mm:
A = (1/2)(b1 +b2)h = (1/2)(32 mm +20 mm)(2 mm) = 52 mm^2
The total area of the figure is then ...
80 mm^2 +52 mm^2 = 132 mm^2
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Answer:
A.The mean would increase.
Step-by-step explanation:
Outliers are numerical values in a data set that are very different from the other values. These values are either too large or too small compared to the others.
Presence of outliers effect the measures of central tendency.
The measures of central tendency are mean, median and mode.
The mean of a data set is a a single numerical value that describes the data set. The median is a numerical values that is the mid-value of the data set. The mode of a data set is the value with the highest frequency.
Effect of outliers on mean, median and mode:
- Mean: If the outlier is a very large value then the mean of the data increases and if it is a small value then the mean decreases.
- Median: The presence of outliers in a data set has a very mild effect on the median of the data.
- Mode: The presence of outliers does not have any effect on the mode.
The mean of the test scores without the outlier is:
*Here <em>n</em> is the number of observations.
So, with the outlier the mean is 86 and without the outlier the mean is 86.9333.
The mean increased.
Since the median cannot be computed without the actual data, no conclusion can be drawn about the median.
Conclusion:
After removing the outlier value of 72 the mean of the test scores increased from 86 to 86.9333.
Thus, the the truer statement will be that when the outlier is removed the mean of the data set increases.