Neither P, nor A are on the sketch
I guess P is the upper right corner of the rectangle
and A=(0,1)

P belongs to the line going through (1,0) and B(0,y)
but we don't know the y-coordinate of B 

the triangle is right and isosceles, so pythagoras a²+a²=2² ... 2a²=4 ... a²=2 ... a=sqrt2 
now look at the right triangle BOA
his hypotenuse is AB=sqrt2 and the the kathete OA is 1 
so y²+1²=(sqrt2)² ... y²+1=2 ... y²=1.. y=1
so the coordinates of B are (0,1)

the line going through (1,0) and (0,1) is L(x)=-x+1

P belongs to this line, so the coordinates of P are P(x,-x+1) (0<x<1)

b) so if that's P, the height of the rectangle is -x+1 and the width=2x
so its area A(x)=2x*(-x+1)= -2x²+2x

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

5 0

3 years ago

How to find mean average diviation

Ilia_Sergeevich [38]

To find the mean absolute deviation of the data, start by finding the mean of the data set.Find the sum of the data values, and divide the sum by the number of data values.Find the absolute value of the difference between each data value and the mean: ...Find the sum of the absolute values of the differences.

5 0

3 years ago

6 of 8

Masja [62]

Answer:

$\frac{19}{4}$