At the point when Hannah takes her first sweet from the sack, there is a 6/n chance it is orange.
This is because that there are 6 orange desserts and n desserts altogether.
When Hannah takes out her second sweet, there is a 5/(n-1) chance that it is orange.
This is because there are just 5 orange desserts let alone for an aggregate of n-1 desserts.
The possibility of getting two orange desserts in succession is the main likelihood increased by the second one: 6/n x 5/n–1
The question lets us know that the shot of Hannah getting two orange desserts is 1/3.
So: 6/n x 5/n–1 = 1/3
Now, rearrange this problem.
(6x5)/n(n-1) = 1/3
This gets to be:
30/(n² – n) = 1/3
Times by 3 on both sides:
90/(n² – n) = 1
What's more, doing likewise with (n² – n):
So (n² – n) = 90
Our answer is: n² – n – 90 = 0
Answer:
1/32
Step-by-step explanation:
Since we want to find the probability that all five coins land on heads, we must first find the total number of possibilities. Since there are 2 choices for each coin to land on, heads or tails, the total number of possibilities is 2^5 = 32.
Since there is only one way to to land on all heads, the probability is 1/32.
Answer:
the relation between them are
n(U) = n(X U Y) + n(xūy).
Answer:
<h2>40°</h2>
Step-by-step explanation:
We have parallel lines.
Angles 1 and 2 are alternate angles.
With parallel lines, alternate angles are congruent.
Therefore
