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Snowcat [4.5K]
3 years ago
10

Value for p that makes inequality true p≤-12

Mathematics
1 answer:
Alex787 [66]3 years ago
3 0

Answer:

-12

Step-by-step explanation:

-12 is less than or equal too -12

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3 years ago
Why did I get it wrong ? I’m finding constant B and idk what’s wrong with my step.
Klio2033 [76]

Answer:

\large \boxed{\sf \ \ A=5, \ \ B=-13 \ \ }

Step-by-step explanation:

Hello,

What you did is correct...

(Ax-3)(x-2)=5x^2+Bx+6\\\\\text{*** we develop the left side ***}\\\\Ax^2+(-2A-3)x+6=5x^2+Bx+6

... and you found A by identifying the term in x^2 to get A = 5, right?

<u>What about the other terms?</u>

<u />

We can then identify the like terms:

>>> term in x^2\\

   A = 5

>>> term in x

   -2A+3=B

>>> constant term

   6 = 6

As we know that A=5 it means that B = -2*5-3=-13

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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