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Zigmanuir [339]

3 years ago

7

3/4 -0.8 7/10 -3/4 from least to greatest

2 answers:

Scilla [17]3 years ago

4 0

Answer:

-0.8, -3/4, 7/10, 3/4

mylen [45]3 years ago

3 0

Answer:

-0.8 < -3/4 < 7/10 < 3/4

Step-by-step explanation:

theyre decreasing

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Encuentre el radio y el área de círculos cuya circunferencias tienen las siguientes medidas

Vadim26 [7]

Answer:

Los radios de los círculos son $r_{1} \approx 9.995$ , $r_{2} \approx 2.013$ , $r_{3} \approx 7.592$ , respectivamente.

Las áreas de los círculos son $A_{1} \approx 313.845$ , $A_{2} \approx 12.730$ , $A_{3} \approx 181.077$ , respectivamente.

Step-by-step explanation:

La circunferencia ( $s$ ) se calcula mediante la siguiente fórmula:

$s = 2\pi\cdot r$ (1)

Donde $r$ es el radio del círculo.

Una vez hallado el radio, se determina el área de la figura geométrica ( $A$ ) mediante la siguiente fórmula:

$A = \pi\cdot r^{2}$ (2)

Si conocemos que las circunferencias son $s_{1} = 62.8$ , $s_{2} = 12.65$ y $s_{3} = 47.7$ , respectivamente:

1) Radios de los círculos

$r_{1} = \frac{s_{1}}{2\pi}$ , $r_{2} = \frac{s_{2}}{2\pi}$ , $r_{3} = \frac{s_{3}}{2\pi}$

$r_{1} \approx 9.995$ , $r_{2} \approx 2.013$ , $r_{3} \approx 7.592$

2) Áreas de los círculos

$A_{1} = \pi\cdot r_{1}^{2}$ , $A_{2} = \pi\cdot r_{2}^{2}$ , $A_{3} = \pi\cdot r_{3}^{2}$

$A_{1} \approx 313.845$ , $A_{2} \approx 12.730$ , $A_{3} \approx 181.077$

6 0

3 years ago

Please help me with this question

telo118 [61]

Answer:

C, because minus is difference and plus is the sum

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3 years ago

STALIN [3.7K]

Answer:

answer is I'm guessing B.

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3 years ago

Which statement is true about the given information?

Archy [21]

Answer:

I think the answer is BD ≅ CE

8 0

3 years ago

A diver in the Olympics dives off a platform 15 m above the water’s surface and descends to a depth of 5 m below the surface. Ho

tia_tia [17]

Let the water surface be 0.

He starts at 15 and gets to the water surface of 0 so he travels 15 meters.

He then goes 5 meters below the surface.

15 + 5 = 20 total meters.

8 0

3 years ago

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