Given

,

is in Quadrant IV,

, and

is in Quadrant III, find

We can use the angle subtraction formula of sine to answer this question.

We already know that

.
We can use the Pythagorean identity

to find

.

Since

is in Quadrant IV, and sine is represented as y value on the unit circle, we must assume the negative value

.
As similar process is then done with

.

And since

is in Quadrant III, and cosine in represented as x value on the unit cercle, we must assume the negative value

.
Now we can fill in our angle subtraction formula!
Answer:
10^2*10^2
Step-by-step explanation:
1) Write 100*100 in as powers of 10: 10^2 * 10^2
Answer:
6x-2
Step-by-step explanation:
-4x(1-3)-(2x+2)
= 4x+12x-2x-2
6x-2
(simplify)
Answer: Any number times zero is zero, it can never equal something else.
Step-by-step explanation: My teacher taught me this before so i know :)
The equation is
9 × g = 162
9g = 162
Solving foe Gall's age,
9g = 162
g = 162 ÷ 9
g = 18