Question

Consider the equation below.

Answer 1

The correct equation that can be used is $(t+4)^{2}=3$ ( Option A)

Step-by-step explanation:

Given Equation:

$4 t^{2}-28 t=6 t^{2}-12 t+26$

It can be rearranged as follows,

$6 t^{2}-4 t^{2}+28 t-12 t+26=0$

IT can be simplified as,

$2 t^{2}+16 t+26=0$

Dividing the above equation by 2, we will get,

$t^{2}+8 t+13=0$

Now we have to divide the coefficient of t by 2, we will get 4 and squaring 4, and add that value on both sides of the equation we will get,

$t^{2}+8 t+16=-13+16$

$t^{2}+8 t+16=3$