Answer:
21
*40
<u> </u>
0
+840
<u> </u>
840
105
-80
<u> </u>
40
-40
<u> </u>
0
=105
<u>8 goes into 84 ten times, 84-80 =4</u>
<u>Bring down the zero make 40 which 8 goes into five times</u>
<u></u>
Step-by-step explanation:
cant be round because there no tenths place
<h2>TRANSLATION</h2><h2>
</h2><h3>8 entra en 84 diez veces, 84-80 = 4
</h3><h3>
</h3><h3>Baje el cero, haga 40, en el que 8 entra cinco veces</h3><h3 /><h3>no puede ser redondo porque no hay décimos, asegúrese de poner los números correctos</h3>
Answer:
- (0, 4)
- (-1, 16/ 3)
- (-9/ 2, 10)
Step-by-step explanation:
In an ordered pair the term before the comma is the x variable and the term after the comma is the y variable.
1.
4x + 3y = 12 . . . . . .(0, _)
here were given the x variable
finding the other term
4× 0 + 3y = 12
3y = 12
y = 4
therefore the ordered pair is <u>(0, 4) </u>
2.
. . . . . . . (-1, _)
here were given the x variable
4 × -1 + 3y = 12
3y = 12 + 4
3y = 16
y = 16/ 3
ordered pair is <u>(-1, 16/ 3)</u>
3.
. . . . . . . . (_, 10)
here were given the y variable
finding the other term
4x + 3 × 10 = 12
4x + 30 = 12
4x = 12 - 30
4x = -18
dividing both sides by 2
2x = -9
x = -9/ 2
ordered pair is<u> (-9/ 2, 10)</u>
A = 1/2 bh
A = 1/2 (9)(5)
A = 45/2
A = 22.5
answer
22.5 cm^2
<em>Answer: h = 120 ft; w = 80 ft </em>
<em></em>
<em>A = 9600 ft^2</em>
<em />
<em>Step-by-step explanation: Let h and w be the dimensions of the playground. The area is given by:</em>
<em></em>
<em>A = h*w (eq1)</em>
<em></em>
<em>The total amount of fence used is:</em>
<em></em>
<em>L = 2*h + 2*w + w (eq2) (an extra distance w beacuse of the division)</em>
<em></em>
<em>Solving for w:</em>
<em></em>
<em>w = L - 2/3*h = 480 - 2/3*h (eq3) Replacing this into the area eq:</em>
<em></em>
<em></em>
<em></em>
<em>We derive this and equal zero to find its maximum:</em>
<em></em>
<em> Solving for h:</em>
<em></em>
<em>h = 120 ft. Replacing this into eq3:</em>
<em></em>
<em>w = 80ft</em>
<em></em>
<em>Therefore the maximum area is:</em>
<em></em>
<em>A = 9600 ft^2</em>
<em />