Answer: 2/8.
Step-by-step explanation:
When we have this type of problem, the usual way to solve them is trying with known types of sequences.
I will start with the arithmetic sequence, where the difference between any two consecutive terms is a constant. And if we call this difference as D, we will have the recursive relation:
Aₙ = Aₙ₋₁ + D
To check if this sequence is an arithmetic sequence, we can take the first two terms and see the difference:
(5/8 - 3/4) = (5/8 - 6/8) = -1/8.
Now let's do the same, but with the second and third terms:
(1/2 - 5/8) = (4/8 - 5/8) = -1/8
The difference is the same, -1/8.
Now we can use the recursive relationship above and the last given term of the sequence to find the next one:
A₅ = A₄ + (-1/8)
A₅ = 3/8 - 1/8 = 2/8
Then the next fraction in the sequence was 2/8.
Answer:
x = 11
Step-by-step explanation:
Line A is parallel to line B when the alternate exterior angles at the transversal are congruent:
5x +9 = 6x -2
11 = x . . . . . . . . . add (2-5x) to both sides
The value of x that makes the lines parallel is 11.
Answer:
x = 84
Step-by-step explanation:
The sum of the interior angles of a polygon is
sum = 180° (n - 2) ← n is the number of sides
Here n = 5, thus
sum = 180° × 3 = 540°
Sum the interior angles and equate to 540 for x
131 + 108 + 107 + 110 + x = 540, that is
456 + x = 540 ( subtract 456 from both sides )
x = 84
A. The terms are in standard from and al placeholders are accounted for, including x^2
