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3 years ago

Evaluate the following.

Mathematics

2 answers:

Dominik [7]3 years ago

3 0

Answer:

Step-by-step explanation:

|8| - |14 - 11|

8 - 3

JulsSmile [24]3 years ago

3 0

The answer is 5 because 14 - 11 is 3 & 8 -3 is 5

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Kelvin finished $\frac{2}{3}$ 2 3 of his test in a $\frac{1}{2}$ 1 2 hour. Express this rate in hours per test.

svet-max [94.6K]

Complete Question

Kelvin finished 2/3 of his test in a 1/2 hour. Express this rate in hours per test.

Answer:

3/4 hours per test

Step-by-step explanation:

2/3 of his test = 1/2 hour

This rate in hours per test is calculated as:

x = 1/2 /2/3

x = 1/2 hour ÷ 2/3 test

x = 1/2 × 3/2

x = 3/4 hours per test

This rate in hours per test is given as 3/4 hours per test

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3 years ago

Look at the sections between the whole numbers on the number line below. How many equal parts are in each section? What fraction

noname [10]

You didn’t provide us with an image.

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3 years ago

A pet store holds training classes for dogs. The store has two different training programs. The first program charges a $35 memb

GrogVix [38]

The programs cost the same for 7 classes.

Given, no. of classes is represented by c, no. of dogs is represented by d, no. of hours is represented by h, the no. of programs is represented by p and the total cost is represented by t.

The first program charges $35 membership fee and $5 for each class.

The second program charges only $10 for each class.

Now the total cost say $t_{1}$ , for first program can be written in equation form as,

$t_{1} =35+5c$ , here c is the no. of classes.

Similarly, the total cost say $t_{2}$ , for second program can be written in equation form as,

$t_{2} =10c$ .

We have to find out the no. of classes for which the two programs cost the same.

according to the question,

$t_{1} =t_{2}$

$35+5c=10c\\10c-5c=35\\5c=35\\c=7$

Hence for 7 of classes the programs cost the same.

For more details follow the link:

brainly.com/question/4042361

3 0

2 years ago

Read 2 more answers

Solve for inequality: 9x + 11 > 4x - (17 - 9x)

Soloha48 [4]

$9x + 11 \ \textgreater \ 4x - (17 - 9x) \\
9x + 11 \ \textgreater \ 4x - 17+9x\\
4x\ \textless \ 28\\
x\ \textless \ 7$

6 0

3 years ago

Two vertical poles of length 10 and 12 feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the

Marat540 [252]

Answer:

$L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft$

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

$x^{2} +10^{2}=L_{1} ^{2} \\x^{2} + 100 = L_{1} ^{2}$

Take the square root of both sides

$\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\ \sqrt{x^{2}+100}= L_{1}$

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

$(17-x)^{2}+12^{2}=L_{2} ^{2} \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}$

Take the square root of both sides

$\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}} \\\sqrt{x^{2}-34x+433}=L_{2}$

Amount of cable used, L = L1 + L2

$L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}$

3 0

3 years ago