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german
3 years ago
7

Please help Me solve this ASAP

Mathematics
1 answer:
Crazy boy [7]3 years ago
8 0

Answer:

i dont know it looks complicated

Step-by-step explanation:

copy paste then search it, you might find it.

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In the equation 3x - 9 = 3, what is the first step we should do?
zavuch27 [327]

Anse

draw the line down the equal sign

Step-by-step explanation:

4 0
3 years ago
Solve the two-step equation.-0.45x + 0.33 = -0.66What is the solution?x = -2.2x = -1.4x = 1.4x = 2.2f
Softa [21]

Answer:

x = 2.2

Step-by-step explanation:

-0.45x + 0.33 = -0.66

Subtract .33 from each side

-0.45x + 0.33-.33 = -0.66-.33

-.45x = -.99

Divide each side by -.45

-.45x./-.45 = -.99/-.45

x = 11/5

x = 2.2

8 0
3 years ago
Find the vertex of the function h(x) = x2 – 4x – 21
lakkis [162]

Answer: (2, -25)

Step-by-step explanation:

The x coordinate of the vertex is x=-\frac{-4}{2(1)}=2.

When x=2, h(2)=2^2 - 4(2)-21=-25.

So, the vertex is (2, -25).

7 0
2 years ago
Can someone explain (with steps) how to rationalize the following expression?
insens350 [35]
F(x)=(-2/((x+y-2)^(1/2))-(x+y+2)^(1/2)
the only irrational part of this expression is the (x+y-2)^(1/2) in the denominator, so, to rationalize this, you multiply the numerator and denominator by the denominator, as well as the other parts of the expression
also, you must multiply the -sqrt(x+y+2) by sqrt(x+y-2)/sqrt(x+y-2) to form a common denominator
(-2)/(x+y-2)^(1/2)-(x+y+2)^(1/2)(x+y-2)^(1/2)/(x+y-2)^(1/2)
(common denominator)
(-2-(x^2+xy+2x+xy+y^2+2y-2x-2y-4))/(x+y-2)^(1/2)
(FOIL)
(-2-x^2-y^2-2xy+4)/(x+y-2)^(1/2)
(Distribute negative)
(-x^2-y^2-2xy+2)/(x+y-2)^(1/2)
(Simplify numerator)
(-x^2-y^2-2xy+2)(x+y-2)^(1/2)/(x+y-2)^(1/2)(x+y-2)^(1/2)
(Rationalize denominator by multiplying both top and bottom by sqrt)
(-x^2-y^2-2xy+2)((x+y-2)^(1/2))/(x+y-2)
(The function is now rational)
=(-x^2-y^2-2xy+2)(sqrt(x+y-2))/(x+y-2)
6 0
3 years ago
What is the equation of the points (-3,2) (2,-1) in standard form? 
Evgen [1.6K]
You can just plug in one of the points to each equation until you get an equality that is true.

I chose to use (-3,2)

1. 5x+3y=1
5(-3)+3(2)=1
(-15)+ 6 = 1
(-9) = 1 <<<(FALSE)

2. x+5y=3
(-3)+5(2)= 3
(-3)+10= 3
7=3 <<<(FALSE)

3. 3x+5y=1
3(-3) + 5(2)= 1
(-9)+10=1
1=1<<<(TRUE)

So, the correct equation is 3x+5y=1.

Make sense?
3 0
3 years ago
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