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Neporo4naja [7]
3 years ago
10

Two people start jogging at the same point and time but in opposite directions. If the rate of one jogger is 2 mph faster than t

he other and after 3 hours they are 30 miles apart, what is the rate of the faster jogger
A 3
B 4
C 5
D 6
E 7
Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0

Answer:

D: 6

Step-by-step explanation:

Let x mph be the rate of the faster jogger

Therefore (x-2) mph is the rate of the slower jogger

After 3 hours faster jogger will be 3x miles from the starting point

Whereas after the 3 hours slower jogger will be 3(x-2) miles from the starting point but in the opposite direction.

Since they are 30 miles apart 3x+3(x-2)=30

3x+3x-6=30

⇒ 3x+3x=30 +6

⇒ 6x=36

⇒ x=6

Therefore the rate of the faster jogger = 6 mph

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Brilliant_brown [7]

Answer: 7

Step-by-step explanation:

We found the factors and prime factorization of 28 and 35. The biggest common factor number is the GCF number. So the greatest common factor 28 and 35 is 7.

Hope this helps :)

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3 years ago
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Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long
Ne4ueva [31]

We are given

Jim's backyard:

Length is

L=15\frac{5}{6} =\frac{95}{6} yards

width is

W=10\frac{2}{5} =\frac{52}{5} yards

Since, this is rectangle

so, we can find area of rectangle

A=L*W

A=(\frac{95}{6})*(\frac{52}{5})

A=\frac{494}{3} yard^2

Area of one sod:

length is

l=1\frac{1}{3} =\frac{4}{3} yards

width is

w=1\frac{1}{3} =\frac{4}{3} yards

Since, it is rectangle in shape

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Area=l*w

A=\frac{4}{3}*\frac{4}{3}

A=\frac{16}{9}yard^2

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

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now, we can simplify it

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4 years ago
Ten times a number increased by eighty four equals 194. what is the number
steposvetlana [31]

Answer: x = 11

Step-by-step explanation:

10x+84=194

10x = "10 times a number"

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Subtract 84

10x = 110

Divide by 10

x = 11

<em>Hope it helps <3</em>

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