Question

If you can’t answer seriously then don’t answer at all

Answer 1

The container has a total of 41 possible numbers from which to draw, and so each one as a probability of $\dfrac1{41}$ of being drawn.

Most of these numbers are even (21 of them) and

$P(\text{even})=\dfrac{21}{41}$

20 of these numbers are greater than 30, so

$P(\text{greater than 30})=\dfrac{20}{41}$

and among these, exactly half are even, so that

$P(\text{greater than 30 AND even})=\dfrac{10}{41}$

So we have

$P(\text{greater than 30}\mid\text{even})=\dfrac{P(\text{greater than 30 AND even})}{P(\text{even})}=\dfrac{\frac{10}{41}}{\frac{21}{41}}=\dfrac{10}{21}\approx0.48$