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WINSTONCH [101]
3 years ago
11

The diameter of Jen’s bicycle tire is 30cm. About how many revolutions will her tire make in a 20,000 cm journey?( Use pi =3.14

and round your answer to the nearest whole number)
Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Answer:

213

Step-by-step explanation:

The circumference of the wheel is given by

C=2πr=πd

Where d is diameter, r is radius and c is circumference

The number of revolutions N multiplied by circumference should yield the total distance

N*πd= Distance

Given distance of 20, 000 cm and diameter of 30 cm

30πN=20000

Making N the subject of formula

N=20000/(30π)=212.20659078919378102517835116335248271261

Rounded off, about 213 revolutions are required

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2. A highway makes an angle of 6 with the horizontal. This angle is maintained for a horizontal distance of 5 miles. To the near
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Given:
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3 years ago
Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck
Nimfa-mama [501]
\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}
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Now, isolate the variables, so you can integrate.
(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}
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4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C
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At x = 1, y = 0.
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6 0
3 years ago
If f(x) = x-1/3 and g(x) = 3x+1 what is (fog)(x)
marin [14]

Answer:

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Step-by-step explanation:

f(x) = x-1/3 and g(x) = 3x+1 what is (fog)(x)

f ( g(x) ) =  (3x + 1)  - (1/3) =   3x  + 2/3

Or

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of if you meant  f(x) = x - (1/3) then  f(g (x)) =   3x + 2/3

3 0
3 years ago
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