Determine the area of each semicircle or quarter circle. Think carefully about whether the length you are given corresponds to a
radius or a diameter. Give your answers to the tenths decimal place (1 decimal such as 3.4) and DO NOT include the units because it is very difficult to do in the answer field because these are all squared. Use 3.14 for LaTeX: \piπ. Remember the formula for Area of a Circle is: LaTeX: A=\pi r^{^2}
1 answer:
Answer:
Area of semicircle = 1/2(πr^2)
Area of quarter circle = 1/4(πr^2)
Step-by-step explanation:
The question is incomplete. You didn't provide the diagrams for the semicircle and quarter circle to evaluate the areas. I would explain how to find the area of a semicircle and quarter circle.
Area of a circle = πr^2
where r = radius and π = 3.14
If diameter (d) is given: d = 2r
To get radius, divide diameter by 2.
r = d/2
A semicircle is half of a circle.
Area of a semicircle is half the area of a circle.
Area of a semicircle = 1/2(πr^2)
A quarter circle is a quarter of a circle.
Area of a quarter circle is quarter of the area of a circle.
Area of a quarter circle = 1/4(πr^2)
Further explanation with diagram has been added as as an attachment.
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Answer:
A.
C.
Step-by-step explanation:
Given:
The given line is
Express this in slope-intercept form , where m is the slope and b is the y-intercept.
Therefore, the slope of the line is .
Now, for perpendicular lines, the product of their slopes is equal to -1.
Let us find the slopes of each lines.
Option A:
On comparing with the slope-intercept form, we get slope as .
Now, . So, option A is perpendicular to the given line.
Option B:
For lines of the form , where, a is a constant, the slope is undefined. So, option B is incorrect.
Option C:
On comparing with the slope-point form, we get slope as .
Now, . So, option C is perpendicular to the given line.
Option D:
On comparing with the slope-intercept form, we get slope as .
Now, . So, option D is not perpendicular to the given line.