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3 years ago

10

Are 5(2x-y) and 15x-5y equivalent expressions?

1 answer:

krek1111 [17]3 years ago

6 0

No, they are not equivalent.

5(2x - y) = 10x - 5y and it is not equal to 15x - 5y.

(using distribution property)

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Which equation and solution can be used to solve this problem?

maks197457 [2]

Answer:

D

Step-by-step explanation:

We need to convert these words into mathematical expressions:

- "Twenty-two less than a number"; "less than" indicates that we need to use subtraction, and since it's "twenty-two less than", we have: -22. Let's say the "number" is q. Then, we have -22 of q, which is q - 22.

- "is twenty-four"; "is" in math always means "equal", so we need an equal sign with 24 next to it: = 24

Put this altogether:

q - 22 = 24

The answer is thus D.

4 0

3 years ago

Read 2 more answers

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

3 years ago

Please answer this correctly

saw5 [17]

Answer:

i think it might be 16

Step-by-step explanation:

pls correct me if im wrong

7 0

2 years ago

Read 2 more answers

A wise man once said, “200 reduced by 3 times my age is 29.” What’s is his age?

ehidna [41]

The man's age is 57 years old.

To find this answer follow the steps below:

1. Subtract 29 from 200 to get 171.

2. Divide 171 by 3 to get 57.

To check this, use the equation 200 - (57 x 3) = 29.

1. 57 x 3 = 171. 200 - 171 = 29

2. 200 - 171 = 29. 29 = 29.

Thus meaning the man is 57 years old. I hope this helps!

4 0

3 years ago

Read 2 more answers

Pls help on algebra homework. Will mark brainliest!

Over [174]

Answer:

H)

Step-by-step explanation:

First, Length XY is 20 centimeters. Since YZ = 3/5 XY, $\frac{3}5\times20=12$

YZ = 12 + 20 = 32 cm, hence H)

Hope you have a nice day! (Pls mark brainliest)

4 0

1 year ago