Answer:
3(-1)-5-6(-1)-2. You found the value of X, so you need to put it back into the equation to see if it equals out.
Answer:
No ;
Step-by-step explanation:
Given ;
s2 = 10 ; n2 = 10 ; s1 = 12 ; n1 = 12
Hypothesis :
H0 : σ1² = σ2²
H1 : σ1² ≠ σ2²
The test statistic :
Ftest = s1² / s2² = 12² / 10² = 144 / 100 = 1.44
The Pvalue using the Pvalue from Ftest calculator :
Numerator df = 12 - 1 = 11
Denominator df = 10 - 1 = 9
Pvalue = 0.2969
At α = 0.1
If Pvalue > α ; Fail to reject H0
0.2969 > 0.1 ; Hence, we fail to reject the Null
Hence, we cannot conclude that variation exists
Answer:
the second
Step-by-step explanation:
Answer:
do you have a photo I don't get it not being funny do you have a photo or something I'm trying to help as much as I can
