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aleksklad [387]

2 years ago

15

You roll a six-sided number cube and flip a coin. What is the probability of rolling a number greater than 3 and flipping heads?

Write your answer as a fraction in simplest form.

1 answer:

alekssr [168]2 years ago

3 0

(4,h)
(5,h)
(6,h) N(s)=6*2=12 n(a)=3 p(a)=0.25

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A bag contains 4 white, 3 black, and 6 green balls. Balls are picked at random. Explain why the events picking a white ball and

Fofino [41]

Answer: D

Step-by-step explanation:

D is the correct answer because first of all, there are 13 balls total. So the denominator would have to be 13. Also, white is the second largest number of balls in the set, so it is pretty likely that you will pick it. Although the most common picked would be green since it has the most balls.

4 0

3 years ago

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What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve.x = + √7/9 and x = ±1 x = + √7/9 and x = ±

snow_tiger [21]

Answer:

Step-by-step explanation:

9x⁴ – 2x² – 7 = 0

Let's say that u = x²:

9u² – 2u – 7 = 0

Factor:

(u – 1) (9u + 7) = 0

u = 1, -7/9

Since u = x²:

x² = 1, -7/9

x = ±1, ±i √(7/9)

6 0

3 years ago

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√−100 = ___ +_____i<br> ...

Natalija [7]

Answer:

Step-by-step explanation:

Rewrite this as

$\sqrt{(-1)(100)}$

Knowing that i-squared = -1:

$\sqrt{(i^2)(100)}$

Both i-squared and 100 are perfect squares, so this simplifies to

±10i

7 0

2 years ago

A state end-of-grade exam in American History is a multiple-choice test that has 50 questions with 4 answer choices for each que

Assoli18 [71]

Answer:

Q1) The student has a 0.01% probability of passing the test.

Q2) She has a 99.91% probability of passing in the test.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he gets it correct, or he gets it wrong. So we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

Question 1.

There are 50 questions, so $n = 50$ .

The student is going to guess each question, so he has a $\pi = \frac{1}{4} = 0.25$ probability of getting it right.

He needs to get at least 25 question right.

So we need to find $P(X \geq 25)$ .

Using a binomial probability calculator, with $n = 50$ and $\pi = 0.25$ we get that $P(X \geq 25) = 0.0001$ .

This means that the student has a 0.01% probability of passing the test.

Question 2.

Now, we need to find $P(X \geq 25)$ with $\pi = 0.70$ . So $P(X \geq 25) = 0.9991$

She has a 99.91% probability of passing in the test.

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3 years ago

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2 different ways to write x/-7 in words

Ronch [10]

Answer:

X divided by negative seven

x over negative seven (my personal favorite) :)

hope I could be of assistance.

4 0

3 years ago