Question

Inverse of y=log(x+1)

Answer 1

$y=log_{10}(x+1) \\ 10^y = x+1 \\ x = 10^y-1 \\ f^{-1}(x) = 10^x - 1$

Answer 2

$f(x) = log(x + 1)$
$y = log(x + 1)$
$x = log(y + 1)$
$10^{x} = y + 1$
$10^{x} - 1 = y$
$10^{x} - 1 = f^{-1}(x)$