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BlackZzzverrR [31]
3 years ago
10

Write 13/9 as a mixed number

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0
\frac{13}{9}=\frac{9+4}{9}=\frac{9}{9}+\frac{4}{9}=\boxed{1\frac{4}{9}}
Soloha48 [4]3 years ago
5 0

Answer: 1 and 4/9

Explanation: To write 13/9 as a mixed number, we divide 9 into 13.

9 divides into 13 once so we put a 1 above the 3.

1 x 9 is 9 and 13 - 9 is 4.

So 9 divides into 13 one time with a remainder of 4.

This means that 13/9 can be rewritten as the mixed number 1 and 4/9.

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Answer:

y = (12 - 4x)/5

Step-by-step explanation:

5y = 12 - 4x

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y = (12 - 4x)/5

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The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative
vagabundo [1.1K]

Considering the vertex of the parabola, the correct statement is given by:

The range of the function is all real numbers less than or equal to 9.

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

  • x_v = -\frac{b}{2a}
  • y_v = -\frac{b^2 - 4ac}{4a}

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point, which means that the range is all real numbers less than or equal to y_v.
  • If a > 0, the vertex is a minimum point, which means that the range is all real numbers greater than or equal to y_v.

In this problem, we have that:

  • a = -1 < 0, hence the vertex is a maximum point.
  • The vertex is (-2,9).

Hence the range is described by:

The range of the function is all real numbers less than or equal to 9.

More can be learned about the vertex of a parabola at brainly.com/question/24737967

#SPJ1

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8) The equation of a line that has a slope of -2 and a y-intercept of 3 is:
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BRAINLIESTTT ASAP!! PLEASE HELP ME :)
Lostsunrise [7]

Answer:

See below  

Step-by-step explanation:

(a) Field lines

A negatively charged particle has an electric field associated with it.

The field lines spread out radially from the centre of the point. They are represented by arrows pointing in the direction that a positive charge would move if it were in the field.

Opposite charges attract, so the field lines point toward the centre of the particle.

For an isolated negative particle, the field lines would look like those in Figure 1 below.

If two negative charges are near each other, as in Figure 2, the field lines still point to the centre of charge.

A positive charge approaching from the left is attracted to both charges, but it moves to the closer particle on the left.

We can make a similar statement about appositive charge approaching from the left.

Thus, there are few field lines in the region between the two particles.

(b) Coulomb's Law

The formula for Coulomb's law is

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