3 years ago

PLEASE help me:( i'm desperate (and dumb): factor 2n^(3)+7n^(2)-2n-7

Mathematics

2 answers:

mario62 [17]3 years ago

4 0

$x {}^{2}(2x + 7) - (2x + 7) \\ (2x + 7)(x {}^{2} - 1) \\ (2x + 7)(x - 1)(x + 1)$

Murljashka [212]3 years ago

4 0

2n^(3)+7n^(2)-2n-7

factor by grouping

2n^3 -2n + 7n^2-7

2n(n^2-1) + (7(n^2-1)

factor n^2-1 out

(n^2-1) (2n+7)

factor (n^2-1)

(n-1) (n+1) (2n+7)

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Let's solve this problem step-by-step

Let's set:

2x + 6y = 36 -- equation 1

x + 4y = 20 -- equation 2

(equation 2) * 2

2x + 8y = 40 -- equation 3

(equation 3) - (equation 1)

2y = 4

y = 2 -- equation 4

Plug (equation 4)'s value of y into (equation 2)

x + 4(2) = 20

x = 20 - 8

x = 12

Thus x = 12 and y = 2

Let's check, by substituting these values

$2x + 6y = 36\\2(12)+6(2) = 36\\24+12=36\\36=36\\\\x+4y=20\\12+4(2)=20\\12+8=20\\20=20$

Answer: x = 12 and y = 2

Hope that helps!

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