All categories

3 years ago

What is the first step in sketching the graph of a rational function?

Mathematics

2 answers:

MAVERICK [17]3 years ago

8 0

Consider the rational function

$f(x)=\frac{P(x)}{Q(x)}$

We will find the Domain of Rational function first, means those value of rational function for which f(x) is defined, To do this we will evaluate those point first for which, Q(x)=0.

So, The first Step is "Finding Domain of the rational function" as well as the point where function is not defined.

⇒Consider the function

$f(x)=\frac{x-3}{x-2}$

→Domain of the function is

x-2=0

x=2

=All Real Numbers , except at x=2.

=R- {2}

xxMikexx [17]3 years ago

3 0

Answer:

Step-by-step explanation:

Find the x-value that makes the denominator zero. This x = a is the equation of the vertical asymptote. Next, determine the behavior of the function as x increases without bound in either direction. If there is a limiting value, then this y = d is the horizontal asymptote.

You might be interested in

Jimmy threw a baseball in the air from the roof of his house. The path followed by the baseball can be modeled by the function f

erastovalidia [21]

Answer:

Step-by-step explanation:

The first part of A is easy. Look at the quadratic function, and the constant, the very last number with no t stuck to it represents the height from which the object in question was originally launched. Our constant is 40, so the height of the roof from which the baseball was thrown is 40 feet. Part 2 of A is not quite as simple because it requires factoring using the quadratic formula.Before we do that, let's make our numbers a bit more manageable, shall we? Let's factor out a -8 to get

$f(t) = -(t^2-6t-5)$ and a = 1, b = -6, c = -5.

Filling in the quadratic formula now looks like this:

$t=\frac{6+-\sqrt{6^2-4(1)(-5)} }{2(1)}$ and

$t=\frac{6+-\sqrt{36+40} }{2}$ and

$t=\frac{6+-\sqrt{56} }{2}$ so the 2 solutions are

$t=\frac{6+\sqrt{56} }{2}=6.74sec$ and

$t=\frac{6-\sqrt{56} }{2}=-.742sec$ and since we know time can NEVER be negative, the time it takes for the baseball to hit the ground from a height of 40 feet is 6.74 seconds. Onto part B.

In order to determine exactly how high the baseball did go, we have to find the vertex of the function. We do this by completing the square and getting the function into vertex, or work, form. Begin by setting the quadratic equal to 0, moving over the constant, and then factoring out the leading coefficient. The rule for completing the square are kinda picky in that you have to have a 1 as the leading coefficient, and righ now ours is a -8. So following the rules I stated above:

$-8(t^2-6t)=-40$ Next is the take half the linear term, square it, and then add it to both sides. Our linear term is a -6. Half of -6 is -3, and -3 squared is 9, so we add 9 into the parenthesis first:

$-8(t^2-6t+9)=-40+??$

Because this is an equation, we can't add 9 to one side without adding the equivalent to the other side. But, we cannot forget about that -8 sitting out front there, refusing to be ignored. We didn't just add in a 9, we actually added in a -8 times 9 which is -72. That's what goes on the right side in place of the ??.

$-8(t^2-6t+9)=-40-72$

The reason we complete the square is found on the left side of the equals sign. We have, in the process of completing the square, formed a perfect square binomial that will serve as the h in our vertex (h, k) where h is the number of seconds it takes for the baseball to reach its max height of k, whatever k is. That's what we have to find out. Putting the left side into its simplified perfect square binomial and adding the numbers on the right gives us:

$-8(t-3)^2=-112$

For the last step, add over the -112 and set it back equal to f(t):

$-8(t-3)^2+112=f(t)$ From that we determine that the vertex is (3, 112). The max height of this baseball was 112 feet...so no, it did not make it up to the height of 120 feet that Jimmy wanted for the baseball.

6 0

2 years ago

Cherie is jogging around a circular track. She

skelet666 [1.2K]

Answer:

Measure of minor angle JOG is $95.5^{\circ}$

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.

$\therefore m JG = 200 yards, JO=120 yards$ .

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle $\angle JOG = \theta$ .

To calculate the central angle, use the arc length formula as follows.

$Arc\:Length\left(s\right) = r\:\theta$

Where $\theta$ is measured in radian.

Substituting the value,

$200=120\:\theta$

Dividing both side by 120,

$\dfrac{200}{120}=\theta$

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

$\therefore \dfrac{5}{3}=\theta$

Therefore value of central angle is $\angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}$ , since angle is in radian

Now convert radian into degree by using following formula,

$1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}$

So multiplying $\theta$ with $\left(\dfrac{180}{\pi}\right)^{\circ}$ to convert it into degree.

$\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}$

Simplifying,

$\therefore \theta = 95.49^{circ}$

So to nearest tenth, $\angle JOG=95.5^{circ}$

8 0

3 years ago

Is the constant rate increasing or deceasing

nadezda [96]

Increasing most likely

3 0

2 years ago

Read 2 more answers

On a snowy evening only 2/3 of the registered students in Bob's chess

OLga [1]

18 / 2 = 9 || 9 x 3 = 27. Therefore, 27 students are registered in Bob’s class.

8 0

2 years ago

HELP.... please??????????????

Nostrana [21]

Answers:

Functions

y = -x+11
y = 2x^2-6x+4
y = -7

Not functions

x = 3
x^2+y^2 = 81
y^2 = -5x-12

=======================================================

Explanation:

A function is possible if and only if any given x input leads to exactly one y output.

For something like x^2+y^2 = 81, we can see that x = 0 leads to either y = 9 or y = -9. So this would <u>not</u> be a function. We would need x to pair with only y value to have it be a function.

We have the same thing going on with y^2 = -5x-12 as well.

For anything of the form x = k, where k is any real number, this is also not a function. We have one single input only and it leads to infinitely many outputs. So in a sense, this is even worse compared to the other examples.

-----------------

In summary, we have these three non-functions:

x = 3
x^2+y^2 = 81
y^2 = -5x-12

Everything else is a function. You can use the vertical line test as a visual way to check.

8 0

3 years ago