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olga nikolaevna [1]
3 years ago
13

Jane think of a number . She divides it by six and adds two. She gets an answer of 9. What number was she thinking of?

Mathematics
1 answer:
torisob [31]3 years ago
3 0
The unknown number is X; x/6+2=9; X/6=7; X=42; The answer is 42
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Simplify by combining like terms:<br> 5a + 2b - 3b + 4
padilas [110]
Answer: 5a-b+4

Steps:

Reorder and gather like terms

5a+(2b-3b)+4

Collect coefficients of liked terms

5a+(2-3)*b+4

Calculate the sum or difference

5a-b+4

FINAL Answer: 5a-b+4
8 0
2 years ago
Read 2 more answers
At a concert , there was three grades of seats available Grade A is the most expensive Grade B is the middle price and Grade C S
horsena [70]

The cost of other seats £40 and £24.

<h3>What is ratio?</h3>

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

Given ratio: A: B : C = 5 : 3 :2

let the common ratio be 'x'.

Grade A cost = 5x

Grade B cost = 3x

Grade C cost = 2x

cheapest seats the concert £16

So,

2x=16

x=8

Now, Grade A cost = 5x = 5*8 = £40

Grade B cost = 3x= 3*8 = £24.

Learn more about ratio here:

brainly.com/question/13419413

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4 0
2 years ago
How long does it take for a car to travel 250 feet at 35 mph?
DedPeter [7]
A little over 7 hours
5 0
3 years ago
Country Motorbikes Incorporated finds that it costs $400 to produce each motorbike, and that fixed costs are $1600 per day. The
faltersainse [42]

Answer:

30units,2900

Step-by-step explanation:

Given that Country Motorbikes Incorporated finds that it costs $400 to produce each motorbike, and that fixed costs are $1600 per day.

The price function is p(x) = 700 − 5x, where p is the price (in dollars) at which exactly x motorbikes will be sold.

If x units are produced and sold we have

Costs for x units = variable costs *x +Fixed costs = 400x+1600

Sales revenue = no of units sold * price = x(700-5x) = 700x-5x^2

Profit funciton = P(x) = Sales revenue - Total cost

= 700x-5x^2-400x-1600\\=300x-5x^2-1600

To get maximum profit we use derivative test I derivative =0 and II derivative =negative

P'(x) = 300-10x\\p"(x) = -10

Producing 30 units will maximize the profit.

Max profit

=P(30) = 2900

8 0
4 years ago
PLEASE HELP ME ASAP!
AleksandrR [38]

Ok so first we find the equation that equals one variable.


2y = -x + 9

3x - 6y = -15


We solve for y.


2y = -x + 9

y = -x/2 + 9/2


Then we plug in this y value into the other equation to keep only one variable so we can solve for it.


3x - 6y = -15

3(-x + 9/2) - 6y = -15

-3x + 27/2 - 6y = -15

-9y + 27/2 = -15

-9y = 3/2

-y = 3/18

y = -3/18


Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.


y = -x/2 + 9/2

-3/18 = -x/2 + 9/2

-84/18 = -x/2

-x = 9 1/3

x = -28/3


Your answer would be (-28/3, -3/18)


Hope this helps!

6 0
4 years ago
Read 2 more answers
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