The first term, a, is 2. The common ratio, r, is 4. Thus,
a_(n+1) = 2(4)^(n).
Check: What's the first term? Let n=1. Then we get 2(4)^1, or 8. Is that correct? No.
Try this instead:
a_(n) = a_0*4^(n-1). Is this correct? Seeking the first term (n=1), does this formula produce 2? 2*4^0 = 2*1 = 2. YES.
The desired explicit formula is a_(n) = a_0*4^(n-1), where n begins at 1.
Answer:
(7,3)
Step-by-step explanation:
difference is 4.5x and -.5y
so apply to (2.5,3.5) and you get (7,3)
Answer:
x=9 x=-1
Step-by-step explanation:
x²-8x-9=0 a=1 b=-8 c=-9
you have to use the quadratic formula to get the values.
Subtract 76 on both sides:
2401 - 76 = 76 - 2x - 76
2325 = -2x
Divide both sides by -2:
-1162.5 = x
Answer:
Step-by-step explanation:
Those are the side lengths not the angles so I'm not sure, also are you sure that's right? I believe there has to be a hypotenuse and the hypotenuse is the sum of the two shorter sides added together.
Do you have any more information? I can try to help :)
