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Harman [31]
3 years ago
7

X=y-8 and -x-y=0 solve by substitution

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
7 0

Answer:

y=4

Step-by-step explanation:

x=y-8

-x-y=0

-(y-8)-y=0

Distribute the negative

-y+8-y=0

Combine the like terms

-2y+8=0

-8 (to both sides)

-2y=-8

Divide by -2

y=4

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Cos(x+y)/cosxcosy+tanxtany=1
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Answer:

See explanation

Step-by-step explanation:

Use formula

\cos (x+y)=\cos x\cos y-\sin x\sin y

Substitute it into the first fraction:

\dfrac{\cos (x+y)}{\cos x\cos y}\\ \\=\dfrac{\cos x\cos y-\sin x\sin y}{\cos x\cos y}\\ \\=\dfrac{\cos x\cos y}{\cos x\cos y}-\dfrac{\sin x\sin y}{\cos x\cos y}\\ \\=1-\dfrac{\sin x}{\cos x}\cdot \dfrac{\sin y}{\cos y}\\ \\=1-\tan x\tany

Consider the whole expression:

\dfrac{\cos (x+y)}{\cos x\cos y}+\tan x\tan y\\ \\=1-\tan x \tan y+\tan x\tan y\\ \\=1

Done!

6 0
3 years ago
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Step-by-step explanation:

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From the question the equation is

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Comparing with the general equation above

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Hope this helps you

5 0
4 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:


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