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Harman [31]
3 years ago
7

X=y-8 and -x-y=0 solve by substitution

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
7 0

Answer:

y=4

Step-by-step explanation:

x=y-8

-x-y=0

-(y-8)-y=0

Distribute the negative

-y+8-y=0

Combine the like terms

-2y+8=0

-8 (to both sides)

-2y=-8

Divide by -2

y=4

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Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of si
kozerog [31]

The ratios of sin x° and cos y° are 15/8.

We have given that,

Use the image below to answer the following question.

We have to determine to find the value of sin x° and cos y°.

By applying Pythagoras theorem in the triangle given in the picture,

<h3>What is the Pythagoras theorem?</h3>

(Hypotenuse)² = (leg 1)² + (leg 2)²

PO² = (15)² + 8²

PO² = 225 + 64

PO = √289

PO = 17

By applying the sine rule in the given triangle,

sin(x°) = Opposie side/hypotenous

         = 15/17

cos(y°) = Adjucent side/hypotenous

          = 8/17

The relation between the ratio of sin(x) and cos(x) will be,

\frac{sinx}{cosx} =\frac{\frac{15}{17} }{\frac{8}{17} }

=\frac{15}{8}

Therefore the ratios of sin x° and cos y° are 15/8.

To learn more about the trigonometric function visit:

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5 0
2 years ago
Please help me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!#5
Evgen [1.6K]
A is the correct answer.
5 0
3 years ago
(1 point) Consider the function f(x)=−x3+2x2+2x+1 Find the average slope of this function on the interval (−2,6). equation edito
Whitepunk [10]

Answer:

Step-by-step explanation:

Given is a function

f(x)=-x^3+2x^2+2x+1

f(6) = -6^3+2(6^2)+2(6)+1\\=-131\\

f(-2) = -(-2)^3+2(-2)^2+2(-2)+1\\=13

Average slope of this function is change of f(x) in (-2,6)/change of x in (-2,6)

= \frac{-131-13}{8} \\=-18

By mean value theorem there exists a c such that f'(c) = -18

i.e. -3x^2+4x+2 =-8\\3x^2-4x-10 =0\\

Using quadratic formula

x = 2.61, -1.277

Out of these only 2.61 lies in the given interval

c = 2.61

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3 years ago
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