<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
Answer:
32/2 or 16.5
Step-by-step explanation:
Answer:
7777
Step-by-step explanation:
Answer:
88
Step-by-step explanation:
5GP= BP
2BNP= GNP
BP+BNP=333
GP+GNP=225
BNP= 333-BP
BNP= 333-5GP
GP= 225-GNP
GP= 225-2BNP
BNP=333-5(225-2BNP)
BNP=333-1125+10BNP
-9BNP=-792
BNP=88
Hope it helps :)
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