3x - 3y + 9 = 0
The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b). It is also the value of y when x = 0.
To solve for the y-intercept, set x = 0:
3(0) - 3y + 9 = 0
3(0) - 3y + 9 = 0
Subtract 9 from both sides:
- 3y + 9 - 9 = 0 - 9
- 3y = -9
Divide both sides by -3 to solve for y:
-3y/-3 = -9/-3
y = 3
Therefore, the y-intercept is (0, 3).
The x-intercept is the point on the graph where it crosses the x-axis, and has coordinates of (a, 0). It is also the value of x when y = 0.
To solve for the x-intercept, set y = 0:
3x - 3(0)+ 9 = 0
3x -0 + 9 = 0
Subtract 9 from both sides:
3x + 9 - 9 = 0 - 9
3x = -9
Divide both sides by 3 to solve for x:
3x/3 = -9/3
x = -3
Therefore, the x-intercept is (-3,0).
The correct answers are:
Y-intercept = (0, 3)
X-intercept = (-3, 0)
Answer:
-559872
Without adding in the additonal Numbers
-4xy
Step-by-step explanation:
<u><em>Im most likely way off so please, i am Not going to guarantee that this answer is correct </em></u>
<u><em>(This is the first time ive been unsure of my Answer so please take my warning into consideration) </em></u>
<u></u>
Answer:
Step-by-step explanation:
2 - Corresponding angles theorem
6 - Alternate exterior angles theorem
8 - Transitive Property
Work is attached to this post
1+sin²x=2-cos²x
Remenber: sin²x+cos²x=1 ⇒sin²x=1-cos²x
1+sin²x=1+(1-cos²x)=2-cos² x (this is true)
