Question

A bag contains 5 red checkers and 9 black checkers. A checker is selected, kept out of the bag, and then another checker is selected. What is P(black, then red)?

Answer 1

Answer:

P ( Black then Red ) = 0.24725

Step-by-step explanation:

Given:-

- Red Checkers = 5

- Black Checkers = 9

Find:-

A checker is selected, kept out of the bag, and then another checker is selected. What is P(black, then red)?

Solution:-

- We will utilize the fundamental counting principle. A bag contains a total of  ( 5 + 9 ) = 14 checkers in total.

- We will draw two checkers one at a time without replacement.

      First Draw: Black = 9 possible outcomes

                         P ( Black ) = 9 / 14

      Second Draw: Red = 5 possible outcomes

                         P ( Red ) = 5 / 13

- The required probability P(black, then red) for dependent events is given as:

      P ( Black then Red ) = P (Black first draw) * P ( Red second draw)

                                        = ( 9 / 14 ) * ( 5 / 13 )

                                        = 0.24725