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4 years ago

Consider the equation 3p – 7 + p = 13. What is the resulting equation after the first step in the solution?

Mathematics

2 answers:

mart [117]4 years ago

8 0

The first step would be to combine like terms which is 3p and p so your equation would look like:

4p - 7 = 13

In the second step you would add 7 to both sides which would give you:

4p = 20

The third and last step would be to divide both sides with 4 which would give you your answer:

p = 5

butalik [34]4 years ago

6 0

First p=23 and because if u do the math right that is what u should get

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In triangle PQR, Q=72 degrees, R=32 degrees and PR=12. find PQ

Volgvan

Answer:

6.69 to the nearest hundredth

Step-by-step explanation:

Use the law of sines

Let x = PQ

$\frac{sin 72}{12} = \frac{sin 32}{x}$

x sin 72 = 12 sin 32

$x = \frac{12 sin 32}{sin 72}$

x = 6.69 to the nearest hundredth

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3 years ago

Complete the sentence below. The standard deviation of the sampling distribution of x overbarx, denoted sigma Subscript x overb

ella [17]

Answer:

The standard deviation of the sampling distribution of x overbarx, denoted sigma Subscript x overbarσx, is called the standard error of the mean . The standard deviation of the sampling distribution of x overbarx, denoted sigma Subscript x overbarσx, is called the standard distribution of the sample.

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4 years ago

Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang

Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - α)% confidence interval for the population standard deviation is:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

The information provided is:

n = 26

s = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611$

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

$=\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3$