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Maurinko [17]
4 years ago
13

Consider the equation 3p – 7 + p = 13. What is the resulting equation after the first step in the solution?

Mathematics
2 answers:
mart [117]4 years ago
8 0

The first step would be to combine like terms which is 3p and p so your equation would look like:

4p - 7 = 13

In the second step you would add 7 to both sides which would give you:

4p = 20

The third and last step would be to divide both sides with 4 which would give you your answer:

p = 5


butalik [34]4 years ago
6 0

First p=23 and because if u do the math right that is what u should get

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In triangle PQR, Q=72 degrees, R=32 degrees and PR=12. find PQ
Volgvan

Answer:

6.69 to the nearest hundredth

Step-by-step explanation:

Use the law of sines

Let x = PQ

\frac{sin 72}{12}  = \frac{sin 32}{x}

x sin 72 = 12 sin 32

x = \frac{12 sin 32}{sin 72}

x = 6.69 to the nearest hundredth

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3 years ago
Complete the sentence below. The standard deviation of the sampling distribution of x overbarx​, denoted sigma Subscript x overb
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Answer:

The standard deviation of the sampling distribution of x overbarx​, denoted sigma Subscript x overbarσx​, is called the​ standard error of the mean . The standard deviation of the sampling distribution of x overbarx​, denoted sigma Subscript x overbarσx​, is called the standard distribution of the sample.

Step-by-step explanation:

The standard error (SE) of a statistic is the standard deviation of its sampling distribution or an estimate of that standard deviation. It is called the standard error of the mean (SEM) if the parameter or the statistic is the mean.

4 0
4 years ago
Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang
Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population standard deviation is:

CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}

The information provided is:

<em>n</em> = 26

<em>s</em> = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652

\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}

     =\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

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Step-by-step explanation:

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