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Ainat [17]
2 years ago
13

Multiply or divide as indicated. Leave your answer with no factors in the denominator. a^3 b^2 / a^-1 b^-3

Mathematics
1 answer:
ikadub [295]2 years ago
5 0

Answer:

a^4 b^5

Step-by-step explanation:

all you have to do is subtract the exponents in the numerator with the exponents in the denominator.

lets focus on 'a' first.

(3) - (-1)= 3+1= 4

so we get a^4

now lets focus on b

(2) - (-3)= 2+3=5

so we get b^5

put that together to get a^4 b^5

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X-y=-3<br> I just kinda need the answer
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30 points! please help!
stiks02 [169]

Answer:

Therefore

15.

25c^{2}-9

16.

(y+8)(y+1)

17.

(x-3y)(x-7y)

Step-by-step explanation:

15.

(5c^{2} +3)(5c^{2}-3)

Using the Identity (a + b)(a - b) = (a² - b²) we get

Consider here a = 5c and b = 3 then we will have

((5c)^{2} -(3)^{2})=25c^{2}-9    .....as required

16.

y^{2}+9y+8

Here Factorize 8 such that sum up to be 9

∴ 8 × 1  = 8 and 8 + 1 =9

y^{2}+9y+8\\y^{2}+8y+y+8\\y(y+8)+1(y+8)\\(y+8)(y+1) ... as required

17.

x^{2}-10xy+21y^{2}

Here Factorize 21 such that sum up to be -10

∴ -3 × -7  = + 21 and -3 - 7 = - 10

x^{2}-10xy+21y^{2}\\x^{2}-3xy-7xy+21y^{2}\\x(x-3y)-7y(x-3y)\\(x-3y)(x-7y) ........as required

Therefore

15.

25c^{2}-9

16.

(y+8)(y+1)

17.

(x-3y)(x-7y)

4 0
2 years ago
Read 2 more answers
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