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Ainat [17]
3 years ago
13

Multiply or divide as indicated. Leave your answer with no factors in the denominator. a^3 b^2 / a^-1 b^-3

Mathematics
1 answer:
ikadub [295]3 years ago
5 0

Answer:

a^4 b^5

Step-by-step explanation:

all you have to do is subtract the exponents in the numerator with the exponents in the denominator.

lets focus on 'a' first.

(3) - (-1)= 3+1= 4

so we get a^4

now lets focus on b

(2) - (-3)= 2+3=5

so we get b^5

put that together to get a^4 b^5

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10=x/4-8 . Find for x.
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3 years ago
I really need help with this one
Novay_Z [31]

Answer:

28

Step-by-step explanation:

Since B is the midpoint of AC, that means AB = BC. That means 3x+4 = 5x-6. We can now set up an equation to solve for x:

3x+4 = 5x-6

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10 = 2x

x = 5

Now that we know what x is, we can just plug x into the expression of AB and multiply it by 2:

(3*(5)+4)*2

=(15+4)*2

=19*2

=28

(side note: we could have plugged x into the expression of BC as well, but in this case plugging it into AB tends to be easier to solve)

Therefore, the length of AC is 28.

3 0
3 years ago
Can someone help me please
Ulleksa [173]

In geometry, there is a theorem that states: The measure of an angle formed by two secants, two tangents, or a secant and a tangent drawn from a point outside a circle is equal to half the difference of the measures of the intercepted arcs


Therefore, this problem has two secants, so m∠x= 1/2(141-25)

m∠x=1/2(116)

m∠x=58


Hope this helped :)

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3 years ago
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