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Ainat [17]
3 years ago
13

Multiply or divide as indicated. Leave your answer with no factors in the denominator. a^3 b^2 / a^-1 b^-3

Mathematics
1 answer:
ikadub [295]3 years ago
5 0

Answer:

a^4 b^5

Step-by-step explanation:

all you have to do is subtract the exponents in the numerator with the exponents in the denominator.

lets focus on 'a' first.

(3) - (-1)= 3+1= 4

so we get a^4

now lets focus on b

(2) - (-3)= 2+3=5

so we get b^5

put that together to get a^4 b^5

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<u><em>Good morning</em></u>,

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riadik2000 [5.3K]

The prime factor of the 576 is 2^6 * 3^2 and the prime factor of the 64 is 2^6. And the expression \sqrt{\dfrac{576}{64}} is equal to 3.

<h3>What is simplification?</h3>

Simplification is to make something easier to do or understand and to make something less complicated.

Given

The expression is \sqrt{\dfrac{576}{64}}

The prime factor of the 576 will be

576 = 2^6 * 3^2

The prime factor of the 64 will be

64 = 2^6

Then the expression will be

\sqrt{\dfrac{576}{64}} = \sqrt{\dfrac{2^6 * 3^2}{2^6}}\\\\\sqrt{\dfrac{576}{64}} = \sqrt{3^2}\\\\\sqrt{\dfrac{576}{64}} = 3

More about the simplification link is given below.

brainly.com/question/12616840

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