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Ainat [17]
2 years ago
13

Multiply or divide as indicated. Leave your answer with no factors in the denominator. a^3 b^2 / a^-1 b^-3

Mathematics
1 answer:
ikadub [295]2 years ago
5 0

Answer:

a^4 b^5

Step-by-step explanation:

all you have to do is subtract the exponents in the numerator with the exponents in the denominator.

lets focus on 'a' first.

(3) - (-1)= 3+1= 4

so we get a^4

now lets focus on b

(2) - (-3)= 2+3=5

so we get b^5

put that together to get a^4 b^5

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Which expressions have exactly two factors? Choose ALL that apply.
marishachu [46]

Answer: The answer is F.

Step-by-step explanation: It’s F because the number would be multiplied equally because all of the number are multiplied by 2. The rest of them either have variables or variables with numbers in them, which looks kind of funky, so F is the answer. I hope you get it right :). Sorry, if I was late for the reply and if you already figured it out… :(.

4 0
2 years ago
Simplify the expression: 2(4 + 6j)
aniked [119]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{8 + 12j}}}}}

Step-by-step explanation:

\sf{2(4 + 6j)}

Distribute 2 through the parentheses

\longrightarrow{ \sf{2 \times 4  + 2 \times 6j}}

\longrightarrow{ \sf{8  + 12j}}

Hope I helped!

Best regards! :D

8 0
3 years ago
The measure of the hypotenuse is? (side c)
Sliva [168]
Answer: 25
explanation:
7² + 24² = c²
49 + 576 = c²
625 = c²
c = √625
c= 25

or just know some pythagorean triples
4 0
2 years ago
Read 2 more answers
Abby is registering at a Web site and must select a six-character password.The password can contain either letters or digits.
zaharov [31]

Answer:

a. 2176782336 with repeated characters. 1402410240 with no repeated characters.

b. 7964171460 when all letters can be repeated, but not numbers. 118813760 when only one number and letters can be repeated.

I believe that the password with all letters able to repeat and numbers not being able to is the most secure password, because if someone were to guess the password there is a 1/7964171460 chance of guessing the password.

Step-by-step explanation:

A. Since there are 26 different letters and 10 different numbers, there are 36 characters we can type. If characters can be repeated then, there is 2176782336 different passwords, since on all six number there are 36 possibilities each. So, 36 x 36 x 36 x 36 x 36 x 36 or 36^6 is to evaluated to find the answer. If characters are not to be repeated, there are 1402410240 different passwords, since on the first number there are 36, second has 35, third has 34, fourth has 33, fifth has 32, and sixth has 31. So, 36 x 35 x 34 x 33 x 32 x 31 is to be evaluated to solve this.

B. Since all characters that are letters can be repeated, then there are 26 letters to use forever and 10 numbers you can use with a limit. So, 36 x 35 x 34 x 33 x 32 x 31 which is to be solved if only numbers were to be used, which is 1402410240. Then, you add that with 36 x 35^5 and 36 x 35 x 34^4 and 36 x 35 x 34 x 33^3 and 36 x 35 x 34 x 33 x 32^2. which will be 7964171460. If the password must contain one digit, then you must multiply 10 with 26^5. Since, there is 10 different digits to use for the first number and 26 letters to choose from for the other five. So, it will be 26^5 times 10 which is 118813760.

6 0
3 years ago
Describe the end behavior of a 14th degree polynomial with a positive leading coefficient.
kipiarov [429]
The function will enter the graph graph in the upper left hand region and exit in the upper right hand region and overall the graph will be concave upwards.  
For determining the end behavior of a polynomial, there is just 2 things to take notice of. 
1. Is the leading coefficient positive or negative? 
2. Is the degree of the polynomial odd or even?  
For odd ordered polynomials, the curve starts in either quadrant II or III, and ends in quadrant IV, or I. Basically, if it's positive, the curve enters the graph somewhere in the lower left hand region, and exits the graph in the upper right hand region. If the coefficient is negative, it enters in the upper left hand region, and exits in the lower right hand region.  
For even ordered polynomials, the graph is either concave upwards (positive leading coefficient) or concave downwards (negative leading coefficient).  
In this problem, 14 is an even number and since the coefficient is positive, the function will enter the graph graph in the upper left hand region and exit in the upper right hand region and overall the graph will be concave upwards.
4 0
2 years ago
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