If 27.50 mL of 0.120 M NaOH neutralizes 0.248 g of HAA, what is the molar mass of unknown amino acid
1 answer:
Answer:
75.15 g/mol
Explanation:
First, let us look at the equation of reaction;
From the balanced equation of reaction, 1 mole of NaOH is required to completely neutralize 1 mole of HAA.
Recall that: mole = molarity x volume.
Therefore, 27.50 mL, 0.120 M NaOH = 0.0275 x 0.120 = 0.0033 moles
0.0033 mole of NaOH will therefore requires 0.0033 moles of HAA for complete neutralization.
In order to find the molar mass of the unknown amino acid, recall that:
<em>mole = mass/molar mass</em>, hence, <em>molar mass = mass/mole</em>.
Therefore, molar mass of HAA = 0.248/0.0033 = 75.15 g/mol
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