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Lilit [14]
4 years ago
11

How many grams of nitroglycerin are needed to produce 25.0 grams of CO2

Chemistry
1 answer:
LekaFEV [45]4 years ago
8 0
N<em>itroglycerin  decomposes    according  to   the   following  equation

4 C3H5N309  --->  12 CO2 +  10 H20  +  6 N2 +O2
The  moles  of  CO2 =  25 /44(molar  mass  of  CO2)=  0.568  moles

the  mole  ratio  of  C3H5N3O9  to  CO2  IS  4:12   from  equation  above
therefore  the  moles  of  C3H5N3O9=( 0.568 x 4)/12= 0.189  moles
mass  of C3H5N3O9=moles  x  molar  mass  of  C3N5N3O9

That  is    0.189 mol x  227  g/mol=  42.903  grams</em>
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if 3.26 g is dissolved in enough water to make exactly 323 ml of solution, what is the molar cocentration of nitrate ion g
AnnyKZ [126]
Divide both sides to get 104 and that’s your answer
5 0
3 years ago
How many valence electrons are in N2O? SeCl2? PBr3?
8090 [49]
Here is the answer for the three of them
<span>N20 = 16 e-
</span><span>SeCl2 =20
</span><span>PBr3 = 26 
Remember that t</span><span>o find the valence electrons in an atom you need to identify what group the element is in. An element in group 1A has 1 valence electron. If the element is in group 2A, then it has two valence electrons.</span>
5 0
3 years ago
How many elements and atoms are in marble
DochEvi [55]

Answer:

Explanation:

Scientists know that there are 6x1023 molecules in a mole - so we have about 0.5x1023 molecules in our marble…and since every silicon dioxide molecule has one atom of silicon and two of oxygen, we have a grand total of 1.5x1023 atoms. That's 150,000,000,000,000,000,000,000 atoms

7 0
3 years ago
2. if 0.20 m fe3 had been used instead of 0.020 m fe3 , how would the numerical value of the rate constant and the activation en
dezoksy [38]

the calculated value is Ea is 18.2 KJ and A is 12.27.

According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.

At 500K, K=0.02s−1

At 700K, k=0.07s −1

The Arrhenius equation can be used to calculate Ea and A.

RT=k=Ae Ea

lnk=lnA+(RT−Ea)

At 500 K,

ln0.02=lnA+500R−Ea

500R Ea (1) At 700K lnA=ln (0.02) + 500R

lnA = ln (0.07) + 700REa (2)

Adding (1) to (2)

700REa100R1[5Ea-7Ea] = 0.02) +500REa=0.07) +700REa.

=ln [0.02/0 .07]

Ea= 2/35×100×8.314×1.2528

Ea =18227.6J

Ea =18.2KJ

Changing the value of E an in (1),

lnA=0.02) + 500×8.314/18227.6

= (−3.9120) +4.3848

lnA=0.4728

logA=1.0889

A=antilog (1.0889)

A=12.27

Consequently, Ea is 18.2 KJ and A is 12.27.

Learn more about Arrhenius equation here-

brainly.com/question/12907018

#SPJ4

5 0
1 year ago
Based on the bond angles in CH4, NH3, and H2O, rank the magnitude of these repulsions. Rank from strongest to weakest repulsion.
morpeh [17]

Answer:

H2O> NH3> CH4

Explanation:

According to valence shell electron pair repulsion theory (VSEPR), bond angles and repulsion of electron pairs depends on the nature of electron pairs on the central atom of the molecule. Lone pairs cause more repulsion (and distortion of bond angles) than bond pairs). Lone pair- lone pair repulsion is greater than lone pair bond pair repulsion.

Water contains two lone pairs on oxygen hence it experiences the greatest repulsion. Ammonia has only one lone pair on nitrogen hence there is lesser repulsion between lone pairs and bond pairs. Methane possess only bond pairs of electrons hence it has the least repulsion.

4 0
3 years ago
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