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Lilit [14]
3 years ago
11

How many grams of nitroglycerin are needed to produce 25.0 grams of CO2

Chemistry
1 answer:
LekaFEV [45]3 years ago
8 0
N<em>itroglycerin  decomposes    according  to   the   following  equation

4 C3H5N309  --->  12 CO2 +  10 H20  +  6 N2 +O2
The  moles  of  CO2 =  25 /44(molar  mass  of  CO2)=  0.568  moles

the  mole  ratio  of  C3H5N3O9  to  CO2  IS  4:12   from  equation  above
therefore  the  moles  of  C3H5N3O9=( 0.568 x 4)/12= 0.189  moles
mass  of C3H5N3O9=moles  x  molar  mass  of  C3N5N3O9

That  is    0.189 mol x  227  g/mol=  42.903  grams</em>
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The work done to compress a gas is 83.0 J. As a result, 27.0 J of heat is given off to the surroundings. Calculate the change in
stellarik [79]

Answer:

ΔU° = 56.0 J

Explanation:

Step 1: Given data

  • Work done to compress the gas (w): 83.0 J (When work is done on the gas, w is positive).
  • Heat given off to the surroundings (q): -27.0 J (When heat is released to the surroundings, q is negative)

Step 2: Calculate the change in the internal energy of the gas (ΔU°)

The internal energy of a gas is the energy contained within it. We can calculate it using the following expression.

ΔU° = q + w

ΔU° = -27.0 J + 83.0 J

ΔU° = 56.0 J

5 0
3 years ago
What does a bomb calorimeter do?
Sunny_sXe [5.5K]
It is a constant-volume type calorimeter that measures the heat of a particular reaction or measures the calorific value of the fuels. Bomb calorimeters are built in such a way that they can withstand the large pressure produced within the calorimeter due to the reaction or burning of fuel.
7 0
3 years ago
Read 2 more answers
Determine the molar concentration of na+ and po4 3- in a 2.25 M Na3 PO4 solution
muminat

Answer:

A. The concentration of Na^+ in the solution is 6.75 M.

B. The concentration of PO4^3- in the solution is 2.25 M.

Explanation:

We'll begin by writing the balanced dissociation equation for Na3PO4.

This is illustrated below:

Na3PO4 will dissociate in solution as follow:

Na3PO4(aq) —> 3Na^+(aq) + PO4^3-(aq)

Thus, from the balanced equation above,

1 mole of Na3PO4 produce 3 moles of Na^+ and 1 mole of PO4^3-

A. Determination of the concentration of Na+ in 2.25 M Na3PO4 solution.

This can be obtained as follow:

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of Na^+.

Therefore, 2.25 M Na3PO4 solution will produce = (2.25 x 3) /1 = 6.75 M Na^+.

Therefore, the concentration of Na^+ in the solution is 6.75 M

B. Determination of the concentration of PO4^3- in 2.25 M Na3PO4 solution.

This can be obtained as follow:

From the balanced equation above,

1 mole of Na3PO4 produce 1 mole of PO4^3-

Therefore, 2.25 M Na3PO4 solution will also produce 2.25 M PO4^3-.

Therefore, the concentration of PO4^3- in the solution is 2.25 M.

7 0
3 years ago
How do you solve this
3241004551 [841]
With your mind. Boom. Lol I'm sorry I don't know I just need points
4 0
3 years ago
Which ones are right to this question?
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The average Kenectic energy

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