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Lubov Fominskaja [6]
4 years ago
10

Name four ways that bacteria are helpful to people

Chemistry
1 answer:
vesna_86 [32]4 years ago
8 0
<span>gives you dairy products 
helps fight disease 
helps digest food 
They are used in the manufacturing of antibiotics.</span>
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What is the definition of thermal expansion
MissTica

Answer:

Thermal expansion is the tendency of matter to change its shape, area, and volume in response to a change in temperature.

Explanation:

8 0
4 years ago
What element is undergoing oxidation in the following reaction?. . CH4(g) +2O2 (g) -&gt; CO2(g) +2H2O(g). . . option . a) C. b)
SVETLANKA909090 [29]
The correct answer is a.) C. Oxidation occurs when an element loses electrons and increases its oxidation state. In the chemical equation, Carbon in CH4 has an oxidation state of 4- while Carbon in CO2 has an oxidation of 4+.
4 0
3 years ago
Read 2 more answers
How many moles of He are in 16 g of the element? 1.0 mol 4.0 mol 8.0 mol 16 mol
Lady bird [3.3K]

Answer: 4 Mole

Explanation:

16/4 = 4

4 0
4 years ago
If a solution containing 51.429 g of mercury(ii) perchlorate is allowed to react completely with a solution containing 16.642 g
OLga [1]
Hg(No3)2  +NaSO4   --->2NaNO3  +  HgSO4(s)
calculate  the moles  of   each  reactant
moles=mass/molar  mass

moles of  Hg(NO3)2=  51.429g/  324.6  g/mol(molar  mass  of  Hg(NO3)2)=0.158  moles

moles Na2SO4  16.642g/142g/mol=  0.117  moles  of  Na2SO4

Na2SO4  is  the  limiting  reagent in  the   equation   and  by  use  mole  ratio  Na2So4  to  HgSO4  is  1:1   therefore  the  moles  of  HgSO4  =0.117  moles

mass  of  HgSO4=moles  x  molar   mass  of  HgSo4=  0.117 g x  303.6g/mol=  35.5212  grams

7 0
4 years ago
Some SO2 and O2 are mixed together in a flask at 1100 K in such a way ,that at the instant of mixing, their partial pressures ar
kakasveta [241]

Answer:

The answer is "\bold{0.525\ \ atm^{-1}}"

Explanation:

Given equation:

2SO_2(g) + O_2(g) \leftrightharpoons 2SO_3(g)

Given value:

\Delta rH =-198.2 \ \ \frac{KJ}{mol}

Kp=1100 \ K

\Delta x = 2-(2+1)\\\\

     = 2-(2+1)\\\\= 2-(3)\\\\= -1

\left\begin{array}{cccc}I\ (atm)&1&0.5&0\\C\ (atm)&2x&-x&2x\\E\ (atm)     &1-2x&0.5-x&2x\end{array}\right

calculating the total pressure on equilibrium=  (1-2x)+(0.5-x)+2x \ atm\\\\

                                                                         = 1-2x+0.5-x+2x\\\\= 1+0.5-x\\\\=1.5-x\\

\therefore \\\\\to 1.50-x= 1.35 \\\\\to 1.50-1.35= x\\\\\to 0.15= x\\\\ \to  x= 0.15\\\\

calculating the pressure in  So_2:

= (1-2 \times 0.15)

= 1-0.30 \\\\ =0.70 \ atm

calculating the pressure in  O_2:

= (0.5- 0.15)\\\\= 0.35 \ atm \\

calculating the pressure in  So_3:

= (2 \times 0.15)\\\\= (.30) \ atm \\\\

Calculating the Kp at 1100 K:

= \frac{(Pressure(So_3))^2}{(Pressure(So_2))^2 \times Pressure(O_2)}\\\\= \frac{0.30^2}{0.70^2 \times 0.35}\\\\= \frac{0.30 \times 0.30 }{0.70\times 0.70 \times 0.35}\\\\= \frac{0.09 }{0.49\times 0.35} \\\\= \frac{0.09 }{0.1715} \\\\=  0.5247 \ \  or \ \  0.525 \ \ atm^{-1}  \\\\

4 0
4 years ago
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