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Mekhanik [1.2K]
3 years ago
14

Numbers that cannot be written as a ratio of two integers; decimals that are non-ending and non-repeating. EX: pi

Mathematics
2 answers:
Nady [450]3 years ago
6 0
Answer. C.
Example. Because pi is irrational and provided as an example, we know that the answer is C. Irrational.
Blababa [14]3 years ago
5 0
Irrational number: Any real number that cannot be written in fraction form is an irrational number.
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The width,w, of a rectangular garden is X -2 the area of the garden is X^3-2X-4 what is an expression for the length of the gard
slamgirl [31]
A=lw \Rightarrow l=\frac{A}{w}
A - area, l - length, w - width

w=x-2 \\
A=x^3-2x-4 \\ \\
l=\frac{x^3-2x-4}{x-2}=\frac{x^3-2x^2+2x^2-4x+2x-4}{x-2}=\frac{x^2(x-2)+2x(x-2)+2(x-2)}{x-2}= \\
=\frac{(x^2+2x+2)(x-2)}{x-2}=x^2+2x+2

The answer is D. x²+2x+2.
3 0
3 years ago
Read 2 more answers
Identify the expression with nonnegative limit values. More info on the pic. PLEASE HELP.
marshall27 [118]

Answer:

\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\  \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right

Step-by-step explanation:

a) \lim _{x\to 3}\:\frac{x^2-10x+21}{x^2+4x-21}=\lim \:_{x\to \:3}\:\frac{\left(x-7\right)\left(x-3\right)}{\left(x+7\right)\left(x-3\right)}=\lim \:_{x\to \:3}\:\frac{x-7}{x+7}=\frac{3-7}{3+7}=-\frac{4}{10}=-\frac{2}{5}

b) \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=\lim \:_{x\to -\frac{3}{2}}\:\frac{\left(2x+3\right)\left(x-4\right)}{\left(2x+3\right)}=\lim \:\:_{x\to \:-\frac{3}{2}}\:\left(x-4\right)=-\frac{3}{2}-4\\ \\ \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=-\frac{11}{2}

c) \lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0

d) \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}

e) \lim _{x\to 3}\:\frac{x^2-8x+15}{x-3}=\lim \:_{x\to \:3}\:\frac{\left(x-3\right)\left(x-5\right)}{x-3}=\lim _{x\to 3}\left(x-5\right)=3-5=-2

f) \lim _{x\to \frac{5}{2}}\left(\frac{2x^2+x-15}{2x-5}\right)=\lim \:_{x\to \:\frac{5}{2}}\frac{\left(2x-5\right)\left(x+3\right)}{2x-5}=\lim \:\:_{x\to \:\:\frac{5}{2}}\left(x+3\right)=\frac{5}{2}+3=\frac{11}{2}

4 0
3 years ago
Solve Systems of Equations Algebracallyy=x+2 y=-3x
Sphinxa [80]

y = x + 2

y = -3x

Do y = -3x in y = x + 2

y = x + 2

-3x = x + 2

-3x - x = 2

-4x = 2

x = -2/4

x = -1/2

Now put x = -1/2 in y = -3x

y = -3x

y = -3.(-1/2)

y = 3/2

5 0
3 years ago
Evaluate the summation of 3 times negative 2 to the n minus 1 power, from n equals 1 to 5. A) −93. B) −33. C) 33. D) 93
lions [1.4K]
∑ ( from n = 1 to n =5 ) 3 · ( -2 ) ^( n -1 )
a 1 = 3 · ( -2 ) ^0 = 3
a 2 = 3 · ( - 2 ) = - 6
a 3 = 3 · 4 = 12
a 4 = 3 · ( - 8 ) = - 24
a 5 = 3 · 16 = 48
3 - 6 + 12 - 24 + 48 = 33
Answer: C ) 33
4 0
2 years ago
Read 2 more answers
The wind is blowing N 35.0 degrees W at 1.60 * 10^2 mph. A plane has an engine speed of 3.20 * 10^2 mph. Where should the pilot
andreyandreev [35.5K]

Answer: 24.2° SouthWest

<u>Step-by-step explanation:</u>

First step: DRAW A PICTURE of the vectors from head to tail <em>(see image)</em>

I created a perpendicular from the resultant vector to the vertex of the given vectors so I could use Pythagorean Theorem to find the length of the perpendicular. Then I used that value to find the angle of the plane.

<u>Perpendicular (x):</u>

 cos 35° = adjacent/hypotenuse

  cos 35° = x/160

→ x = 160 cos 35°

<u>Angle (θ):</u>

sin θ = opposite/hypotenuse

sin θ = x/320

sin θ = 160 cos 35°/320

    θ = arcsin (160 cos 35°/320)

    θ = 24.2°

Direction is down (south) and left (west)

7 0
3 years ago
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