First you write out your equation, which is 28x-42=154. Then you solve you equation. First, add 42 to each side, get 28x=196. Divide both sides by 28, get x=7.

8 0

3 years ago

a. Determine whether the Mean Value Theorem applies to the function f (x )equals ln 15 xf(x)=ln15x on the given interval [1 comm

ivolga24 [154]

Answer:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

$c = e-1 \\$ = 1.71828

Step-by-step explanation:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

You are looking for a point $c$ such that

$\frac{1}{c} = \frac{\ln(15e)-\ln(15*1)}{e-1} = \frac{\ln(15e/15)}{e-1} = \frac{\ln(e)}{e-1} = \frac{1}{e-1}$

You have to solve for $c$ and get that

$c = e-1 \\$ = 1.71828

5 0

3 years ago

16^3x+8^x+6 Could you please give me the steps as well for this problem?

BARSIC [14]

Answer:

x = 2

Step-by-step explanation:

$16^{3x} = 8^{x+6} \\2^{4(3x)} = 2^{3(x+6)} -->$ (16 = $2^{4}$ and 8 = $2^{3}$ )

$2^{12x} = 2^{3x+18}$

Since the base number is 2, the exponents must equal each other.

So:

12x = 3x+18

9x = 18

x = 2

8 0

3 years ago

What is the simplified form of √45 A) √5 B) √9•5 C) 3√5 D)5√3

Kaylis [27]

The simplified form is C .

4 0

2 years ago