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3 years ago

6

4log x-1/2log y+3log z

1 answer:

babymother [125]3 years ago

7 0

Following rules of logs, we can do the following:

log x^4 - log y^(1/2) + log z^3

Combine the first and 3rd factors to get log [x^4*z^3]

Seeing that the neg. sign signifies division, write this new term - log y^(1/2) as a quotient:

[x^4*z^3]
log ----------------
y^(1/2)

Next time, please include the instructions when you present your problem.
Thx.

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Brady recorded the number and color of cars in the parking lot. 45% of the cars in the parking lot were white. If Brady counted

MA_775_DIABLO [31]

Answer:

180 cars

Step-by-step explanation:

Like you can see in the picture, I like to set up a proportion, so 81 over X and 45 over 100. Then, you can cross multiply, so 81 x 100 = 8100 and then divide, 8100 ÷ 45 = 180, your answer!

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3 years ago

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If Angie’s gross pay for 21.5 hours was $282.08, what was her pay per hour?

xxMikexx [17]

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$13.12 per hour

Step-by-step explanation:

Take the total pay and divide by the number of hours

$282.08/21.5 hours

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3 years ago

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Rewrite the following to show that the opposite of a sum is the sum of the opposites.<br> -(1/4 +6)

alina1380 [7]

Answer:

1/4+6

Step-by-step explanation:

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3 years ago

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The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

3 years ago

3/4-5/4m=113/24<br> please show work

bija089 [108]

May need to change into a mixed fraction

6 0

3 years ago