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2 years ago

4log x-1/2log y+3log z

1 answer:

7 0

Following rules of logs, we can do the following:

log x^4 - log y^(1/2) + log z^3

Combine the first and 3rd factors to get log [x^4*z^3]

Seeing that the neg. sign signifies division, write this new term - log y^(1/2) as a quotient:

[x^4*z^3]
log ----------------
y^(1/2)

Next time, please include the instructions when you present your problem.
Thx.

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2 years ago

Launa bought 20 pizzas for a party. How many pieces of pizza will she have if she divides them each into eighths? A 20 B 190 C16

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2 years ago

A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rat

iris [78.8K]

Answer:

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

$n = (\frac{\pi}{8}) (\frac{pr^4}{v})\\$

The implicit derivative with respect to the time would be

$\frac{dn}{dt} = \frac{\pi}{8} ( \frac{r^4}{v} \frac{dp}{dt} + \frac{4pr^3}{v}\frac{dr}{dt} )$

If we multiply everything by dt we get

$dn = \frac{\pi}{8} ( \frac{r^4}{v} dp + \frac{4pr^3}{v} dr})$

Remember that the error is given by $\frac{dn}{n}$ therefore doing some algebra we get that

$\frac{dn}{n} = 4 \frac{dr}{r} + \frac{dp}{p}$

Since, r = 0.006 , dr = 0.00025 , p = 4*105 , dp = 2000 we get that

$\frac{dn}{n} = 0.1714$

Which means that the maximum error for viscosity is 17.14%.

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2 years ago

toby needs 2 4/5 poundscof clay to make one sculpture how many sculptures can he make from 14 pounds of clay show your work

nikklg [1K]

He can make 5 sculptures.

We divide the amount of clay, 14 pounds, by the amount it takes to make one sculpture, 2 4/5 pounds:

14 ÷ 2/45 = 14 ÷ 14/5 = 14/1 ÷14/5 = 14/1 × 5/14 = 70/14 = 5

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2 years ago