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Yakvenalex [24]
3 years ago
14

Find the x-intercepts of the graph y = StartFraction 2 Over x squared EndFraction?

Mathematics
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

The answer is option c.

There are no x-intercepts

Hope this helps

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Truck brakes can fail if they get too hot. In some mountainous areas, ramps of loose gravel are constructed to stop runaway truc
pickupchik [31]

Kinetic engery = -1/2mv^2

Work = Fd

Combine:

-1/2mv^2 - Fd = 0

-1/2mv^2 = (0.30*15000*9.81*cos(6))d = 0

Multiply both sides by 2:

v^2 = 2d(0.30*9.81*cos(6))

Solve for d:

d=v^2 / 2(0.30*9.81*cos96))

v = speed:

d = 35^2 / 2*0.30 * 9.81 * cos(6)

d = 1225 / 5.85376

d = 209.27 meters. Round answer as needed.

7 0
4 years ago
A Jersey is $35 and is 30% off. How much will you save?<br><br> PLEASE HURRY WITH THE ANSWER !
yanalaym [24]

Answer:

You will save $24.50

Step-by-step explanation:

because 35 x0.3= 10.50, therefore 35 - 10.50=24.50 the answer

4 0
3 years ago
Decide whether the equations is a trigonometric function identity, EXPLAIN.
hodyreva [135]

(1) Answer: Identity true

\cos^2x(1+\tan^2x)=\cos^2x(1+\frac{sin^2x}{cos^2x})=\\= \cos^2x\frac{cos^2x+sin^2x}{cos^2x}=1

(2) Answer: Identity true

\sec x \tan x(1-\sin^2x)=\sin x\\\frac{1}{\cos x}\frac{\sin x}{\cos x}(\cos^2x)=\sin x\\\sin x = \sin x


(3) Answer: Identity true

\sin^2(\theta)\csc^2(\theta)=\sin^2(\theta)+\cos^2(\theta)\\\sin^2(\theta)\frac{1}{\sin^2(\theta)}=\sin^2(\theta)+\cos^2(\theta)\\1 = 1


7 0
3 years ago
Which equation represents a circle with a center at (2,-8) and a radius of 11
Taya2010 [7]

Answer:

(x - 2)² + (y + 8)² = 121

Step-by-step explanation:

circle: (x – h)² + (y – k)² = r²   (h , k) center        r: radius

h = 2          k = - 8          r = 11

equation: (x - 2)² + (y + 8)² = 121

8 0
4 years ago
A triangle has one leg of 24 inches and one leg of 10 inches. For the triangle to be a right triangle, what must be the length o
meriva

Answer: 26 inches

Step-by-step explanation:

The hypoteneuse is the longest side in a triangle. From the question, we are already informed that a triangle has one leg of 24 inches and one leg of 10 inches.

To calculate the hypotenuse, we add the square of both legs together which are the opposite and adjacent and then find the square root. This will be

hypotenuse² = 24² + 10²

hypotenuse² = 576 + 100

hypotenuse² = 676

hypotenuse = ✓676

hypotenuse = 26

The hypothenuse is 26 inches

7 0
3 years ago
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